lead acetate
This compound is lead iodide.
The answer depends on the amount of the substance.
PbI2, lead(II) iodide, is an ionic compound. Lead(II) is a metal and iodide is a non-metal, so they typically form ionic bonds.
The reactants in the equation are potassium iodide (KI) and lead(II) nitrate (Pb(NO3)2).
The balanced equation for the reaction between lead(II) nitrate (Pb(NO3)2) and sodium iodide (NaI) to form lead(II) iodide (PbI2) and sodium nitrate (NaNO3) is: Pb(NO3)2 + 2NaI -> PbI2 + 2NaNO3
Lead(II) iodide or plumbous iodide
This is called lead(II) iodide.
This compound is lead iodide.
K2SO4 + Pbl2 are the reactants.
Pbl2
The answer depends on the amount of the substance.
PbI2, lead(II) iodide, is an ionic compound. Lead(II) is a metal and iodide is a non-metal, so they typically form ionic bonds.
The reactants in the equation are potassium iodide (KI) and lead(II) nitrate (Pb(NO3)2).
The balanced equation for the reaction between lead(II) nitrate (Pb(NO3)2) and sodium iodide (NaI) to form lead(II) iodide (PbI2) and sodium nitrate (NaNO3) is: Pb(NO3)2 + 2NaI -> PbI2 + 2NaNO3
PbI2 is the chemical formula for lead (II) iodide, a yellow crystalline compound. It is commonly used in organic synthesis and as a catalyst in certain chemical reactions. Lead (II) iodide is also used as a detector material for gamma rays and X-rays.
The symbol for lead that displays its charge is Pbl2. Lead can have an oxidation of plus 2 or 4. The plus 2 oxidation in lead is the most common.
The reaction that occurs is a double displacement reaction where lead(II) nitrate and potassium iodide switch partners to form solid lead(II) iodide and potassium nitrate solution. This reaction can be represented by the equation Pb(NO3)2 + 2KI -> Pbl2 + 2KNO3.