not sure but try beryllium sulfate tetrahydrate
Beryllium sulfate is considered acidic because when it dissolves in water, it forms beryllium ions (Be2+) and sulfate ions (SO4^2-). The presence of beryllium ions in the solution can react with water molecules to release hydrogen ions (H+), increasing the concentration of free H+ ions in the solution and thus resulting in an acidic pH.
Sulfuric acid + Beryllium Hydroxide → Berylium Sulfate + 2 Water H2SO4 + Be(OH)2 → Be SO4 + 2H2O
The most common hydrated form of copper sulfate is pentahydrate, known as copper(II) sulfate pentahydrate or CuSO4·5H2O. Another hydrated form is trihydrate, with the chemical formula CuSO4·3H2O. These hydrated forms vary in their water content, affecting their physical properties such as color and solubility.
The reaction between ammonia and copper sulfate forms a deep blue complex called tetraamminecopper(II) sulfate, which has the chemical formula [Cu(NH3)4]SO4. This complex is formed as the ammonia molecules displace the water molecules coordinated to the copper ions in copper sulfate.
Yes, mixing copper sulfate with water forms a liquid solution. Copper sulfate dissolves in water to create a homogeneous mixture where the copper ions are suspended in the water molecules.
it contains: iron sulphur and water (Fe2(SO4)3.H2O) i think
Beryllium sulfate is considered acidic because when it dissolves in water, it forms beryllium ions (Be2+) and sulfate ions (SO4^2-). The presence of beryllium ions in the solution can react with water molecules to release hydrogen ions (H+), increasing the concentration of free H+ ions in the solution and thus resulting in an acidic pH.
White copper sulfate is anhydrous, meaning it does not contain water molecules. When water is added to white copper sulfate, it forms a hydrate compound called blue copper sulfate pentahydrate. The water molecules coordinate with the copper ions, causing the compound to change color from white to blue.
Sulfuric acid + Beryllium Hydroxide → Berylium Sulfate + 2 Water H2SO4 + Be(OH)2 → Be SO4 + 2H2O
When water is added to anhydrous copper (II) sulfate, it will undergo an exothermic reaction where the compound absorbs water molecules to form hydrated copper (II) sulfate. The anhydrous copper (II) sulfate changes color from white to blue as it forms the hydrate.
The most common hydrated form of copper sulfate is pentahydrate, known as copper(II) sulfate pentahydrate or CuSO4·5H2O. Another hydrated form is trihydrate, with the chemical formula CuSO4·3H2O. These hydrated forms vary in their water content, affecting their physical properties such as color and solubility.
The reaction between ammonia and copper sulfate forms a deep blue complex called tetraamminecopper(II) sulfate, which has the chemical formula [Cu(NH3)4]SO4. This complex is formed as the ammonia molecules displace the water molecules coordinated to the copper ions in copper sulfate.
No. Beryllium is a metallic element. However, there is a such thing of beryllium oxide, which forms when beryllium combines with oxygen.
Yes, mixing copper sulfate with water forms a liquid solution. Copper sulfate dissolves in water to create a homogeneous mixture where the copper ions are suspended in the water molecules.
It turns into a blue solution of [Cu.6H2O]2+ complex (or hydrated) ions. The blue crystal form of copper sulfate consists of CuSO4.5H2O complex hydrate ion array, the white form is anhydrous CuSO4 (crystal form without H2O)
Yes, sodium sulfate is soluble in water. It forms a clear solution when added to water, as the ionic bonds in sodium sulfate dissociate, allowing the ions to be surrounded by water molecules and dispersed throughout the solution.
Ammonium sulfate dissolved in water forms a homogeneous solution because the ammonium sulfate molecules are evenly distributed throughout the water to create a uniform solution.