Assuming that the questioner meant the formula to be Al(C2H3O2)3, which the questioner probably was unable to write on a normal keyboard, the answer is aluminum acetate.
This is the empirical formula of aluminium acetate.
calcium acetate
Aluminum Acetate
m
Al(C2H3O2)3 - first, aluminium is in the beginning of the equation and acetate needs to be after. Aluminium has a charge of +3 making it Al+3 -acetate has a charge of -1 and its formula is C2H3O2- Using the crossover method, we see that it would take three acetate ions (-1 charge) to balance out the 1 Aluminium Ion (+3 charge). So the final equation should be Al(C2H3O2)3
Al(CH3COO)3
Aluminum hydroxide is the chemical name for the molecular formula Al(OH)3. It is an ionic compound between Al 3+ and OH-. The equation for its disassociation in water is: Al(OH)3(s) + H2O(L) <--> Al 3+ (aq) + 3OH-(aq) + H2O (l).
Aluminum cyanide is a chemical compound also called Al(CN)3.
Al3+(aq) + 3 NO3-(aq) + Li+(aq) + C2H3O2-(aq) → Al(NO3)3(aq) + LiC2H3O2(s)
is Al(C2H3O2)3 ionic or covalent
Al(C2H3O2)3 - first, aluminium is in the beginning of the equation and acetate needs to be after. Aluminium has a charge of +3 making it Al+3 -acetate has a charge of -1 and its formula is C2H3O2- Using the crossover method, we see that it would take three acetate ions (-1 charge) to balance out the 1 Aluminium Ion (+3 charge). So the final equation should be Al(C2H3O2)3
This compound is aluminium chlorate.
It is aluminium nitrate.
Al(C2H3O2)3 + K3PO4 ==> AlPO4 + 3 C2H3O2Kor looked at another way... Al(CH3COO)3 + K3PO4 ==> AlPO4 + 3 CH3COOK
Al(CH3COO)3
Aluminum (I)hydroxide or Aluminum (III) hydroxide
Cr+3 C2H3O2-1 <----- these are the ions and their charges Cr+3 C2H3O2-1 C2H3O2-1 C2H3O2-1 <---- the charges have to add up to zero, so three -1 acetate ions cancel out one +3 chromium ion Cr(C2H3O2)3 <----- simplify
There is no such compound as BaBr3, there is BaBr2, barium bromide.
The compound is neutral; the ions are Al(3+) and (NO3)-.
3 +
Aluminum hydroxide is the chemical name for the molecular formula Al(OH)3. It is an ionic compound between Al 3+ and OH-. The equation for its disassociation in water is: Al(OH)3(s) + H2O(L) <--> Al 3+ (aq) + 3OH-(aq) + H2O (l).