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The min net force magnitude you can have is (20 - 12) = 8 N, when the two forces are directly opposite in directions. When the two forces align, the net force magnitude becomes the maximum, which is equal to (20 + 12) = 32 N. You can guess that the net force magnitude is somewhere between 8 N and 32 N, when the two forces are at an angle other than 0o or 180o.

Let us say the larger force is A and the smaller force is B, at an angle, alpha, to one another. Then the net force magnitude, |C| = |A| + |B|*cos(alpha). The magnitude of C, |C|, depends solely on cos(alpha), since |A| and |B| are fixed. When alpha = 0o, |C|= |A| + |B| (maximal); when alpha = 180o, |C|= |A| - |B| (minimal). Note that max(cos(alpha))=1 and min(cos(alpha))=-1.

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14y ago
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9y ago

Force is a vector quantity. So direction is much more important. Here in this problem both forces though of equal magnitude act in the same direction. So we have to add them. Hence 40 N will be the net force acting on the body. Its direction will be the same as the one in which both parent forces act.

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9y ago

Forces are vector. When adding them together it is necessary to take their directions into account. However, if they are acting in the same direction then their net effect is simply their sum. In this case, therefore, the answer is 40N.

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14y ago

The maximum resultant is 32N, when the directions of the two forces are the same.

The minimum resultant is 8N, when their directions are opposite.

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15y ago

To get highest resultant force you would line them up in the same direction on the same axis, you'd get 32N resultant force.

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9y ago

If those two are the only forces acting on the object and there are no others,
then the net force on it is 40N in the same direction as both of those.

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13y ago

80 N in the direction of the 100 N force.

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12y ago

8 N

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Q: Consider a pair of forces one having a magnitude of 20 N and the other a magnitude of 12N What maximum net force is possible for these two forces what is the minimum net force prossible?
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