H+ + oh- ---> h2o
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
It will be a neutralization reaction and the products will be NaCl and H2O
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
HCl + NaOH --> NaCl + H2O is balanced as you wrote it.But, since sodium is always soluble in water at temperatures below the boiling point of the solution, the net ionic equation for the reaction at temperatures lower than the boiling point would actually be: HCl + OH- --> Cl- + H2OOr, if the hydrochloric acid was already in solution, then simplyH+ + OH- ---> H2O
HCl + NaOH = NaCl + H2O
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
It will be a neutralization reaction and the products will be NaCl and H2O
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
HCl + NaOH = NaCl + H2O
HCl + NaOH --> NaCl + H2O is balanced as you wrote it.But, since sodium is always soluble in water at temperatures below the boiling point of the solution, the net ionic equation for the reaction at temperatures lower than the boiling point would actually be: HCl + OH- --> Cl- + H2OOr, if the hydrochloric acid was already in solution, then simplyH+ + OH- ---> H2O
HCl + NaOH = NaCl + H2O
HCl + NaOH -----> NaCl + H2O
This equation is HCl + NaOH -> NaCl + H2O.
HCl + NaOH = H2O + NaCl is already balanced.
The reactants are HCl and NaOH.
1 HCl + 1 NaOH ---> 1 NaCl + 1 H(OH)