Given any number, it is always possible to find a polynomial of degree 6 that will fit the above numbers and the additional given number.
The simplest position to value rule, in polynomial form, for the above sequence is
Un = (3n3 - 5n2 + 4n - 12)/2 for n = 1, 2, 3, ...
and accordingly, U7 = 412.
The sequence goes up by 5 each time; the first term is two. So the nth term is 2 + 5n. n=50 => 2+50*5 = 252.
252 Use t(n) = 0.5*(n3 + 13n2 + 4n + 34) for n = 1, 2, 3, ...
1/3
252= 6256252= 3906253906252= 1.525878906x10111.525878906x1011=2.328306437x1022
252 12 * 21 = 252 9 * 28 = 252 7 * 36 = 252
392
The sequence goes up by 5 each time; the first term is two. So the nth term is 2 + 5n. n=50 => 2+50*5 = 252.
252 Use t(n) = 0.5*(n3 + 13n2 + 4n + 34) for n = 1, 2, 3, ...
1 3 6 18 36
0.252 as a fraction = 252/1000 or 63/250 in lowest term 0.252 * 1000/1000 = 252/1000 or 63/250 in fraction in lowest term
1/3
252= 6256252= 3906253906252= 1.525878906x10111.525878906x1011=2.328306437x1022
12 terms. Sum_of_ap = n(2a + (n-1)d) ÷ 2 For 43, 39, 35, ... a = 43, d = -4 ⇒ 252 = n(2 x 43 + (n - 1) x -4) ÷ 2 ⇒ 252 = 45n -2n2 ⇒ 2n2 - 45n + 252 = 0 ⇒ (2n - 21)(n - 12) = 0 ⇒ n = 101/2 or 12 101/2th terms do not make sense, so cannot be an answer. Thus 12 terms are needed. What happens is that the sum increases whilst the terms are positive. After 10 terms, the sum is still less than 252. The 11th term is the last positive term and takes the sum over 252; the 12th term is the first negative term and takes the sum back down to 252.
1 inch = 2.54 centimeters252 centimeters x 1 inch/2.54centimeters= 99.21 inchesyou may try the online converter linked below next time
The LCM, or least common multiple of 14 and 252 is 252. 14 x 18 = 252, and 252 x 1 = 252.
252 = 1 x 252 252 = 2 x 126 252 = 3 x 84 252 = 4 x 63 252 = 6 x 42 252 = 7 x 36 252 = 9 x 28 252 = 12 x 21 252 = 14 x 18
30% of 252= 30% * 252= 0.3 * 252= 75.6