t(n) = 3*2n-1
Or just 3*2n
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
It goes up by (24-16) = 8 each time. The first time is 16. So the nth term is 8n + 8.
Looks like 57: 12+9=21, +9=30, +9=39, +9=48, +9=57.
Had it not been for 64, the nth term would be given by t(n) = 3*n2 However, this cannot be the case because then t(4) would have been 48, not 64.
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
3(2^n-1) * * * * * Nearly, but not quite. The correct answer is 3*2n
If 3 is the first term, then the nth term is [ 3 x 2(n-1) ] .
If you mean: 8 28 48 and 68 then the nth term is 20n -12 and so the next number will be 88
It goes up by (24-16) = 8 each time. The first time is 16. So the nth term is 8n + 8.
> since the value rises by nine at each step and the first term is 12 the formula for > the nth term is: 12+(n-1)*9 Which simplifies to Sn = 9n + 3
Looks like 57: 12+9=21, +9=30, +9=39, +9=48, +9=57.
Had it not been for 64, the nth term would be given by t(n) = 3*n2 However, this cannot be the case because then t(4) would have been 48, not 64.
12 x 12 is the same thing as adding 12 twelve times. 12 x 12 = 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 + 12 = 24 + 24 + 24 + 24 + 24 + 24 = 48 + 48 + 48 = 48 +48 +48 ------- = 144
t(n) = (5n3 - 30n2 + 85n - 48)/6 , n = 1, 2, 3, ...
They are: 12, 24, 36 and 48
You are adding by 12. 12 + 12 = 24 24 + 12 = 36 36 + 12 = 48