There are infinitely many formulae that generate that sequence for the first 5 terms, but then give different terms for the 6th and onwards.
However, the simplest formula (and the one that I guess your teacher is expecting) is based on the fact that there is a fixed common difference of 6 between terms, giving t(n) = 6n - 4 for n = 1, 2, 3, ...
They are: nth term = 6n-4 and the 14th term is 80
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
Un = 29 - 9n
It is: 26-6n
a (sub n) = 11 + (n - 1) x d
They are: nth term = 6n-4 and the 14th term is 80
The nth term is: 3n+2 and so the next number will be 20
The given sequence is 11, 31, 51, 72 The nth term of this sequence can be expressed as an = 11 + (n - 1) × 20 Therefore, the nth term is 11 + (n - 1) × 20, where n is the position of the term in the sequence.
The nth term of the sequence is expressed by the formula 8n - 4.
The nth term of this sequence is 3n + 4
It is: nth term = 6n-4
t(n) = 10 - 6n where n = 1, 2, 3, ...
Willies
Give the simple formula for the nth term of the following arithmetic sequence. Your answer will be of the form an + b.12, 16, 20, 24, 28, ...
Given n and any number for the nth term, it is a simple matter to find a rule such that the above four numbers are the first four of a sequence and the given number in the nth position.However, the simple answer for simple questions is Un = 4n
This appears to be a declining arithmetic series. If it is, the next term is 5, because each term is 3 less than the preceding term.=================================The 'N'th term is: [ 23 - 3N ].
720