Literally every single even number less than 1000 is a composite number other than 2 which is prime.
2 100
Is it 99 1/2 (99.5)?
Every second number greater than 2 is an even number.
989. If there is a remainder of 2 when divided by 3, the number is one less than a multiple of 3. If there is a remainder of 4 when divided by 5, the number is one less than a multiple of 5. Thus the number required is one less than a multiple of the lowest common multiple of 3 and 5 (that is 15). So what is needed is an even multiple of 15 less than or equal to 1000: 1000 ÷ 15 = 662/3 Thus the highest even multiple of 15 not greater than 1000 is 66 x 15 = 990, and the required number is 989.
The digit after the hundreds digit is 2 which is less than 5, so the number rounds down: 1023 → 1000 to the nearest hundred.
Check the Fibonacchi number sequences for 2, 3, 5, & 8 (7 is not a Fibonacchi number).
3000 It is 2000 more than 1000 and 2000 less than 5000 To find a halfway point (which is also the average), add the numbers together and divide by 2.
That would be equal to the sum of all positive integers less than 1000 minus the sum of all positive multiples of three that are less than 1000. That would be equal to: (1000 + 1) * (1000 / 2) - 3 * (333 + 1) * (333 / 2) = 1001 * 500 - 1000 * 166.5 = 500500 - 166500 = 334000
Less than 2 million. The number changes daily. It is estimated that we loose about 1000 WWII vets a day.
The greatest possible 'length' comes from the number with the greatest number of prime factors. The greatest number of factors is created by using the smallest prime number, 2, as a factor as many times as possible. Since 2^9=512 and 2^10=1024, the greatest possible 'length' of a positive integer less than 1000 is 9.
It depends: If the whole number is positive then the result is less than the whole number, eg ½ × 2 = 1 < 2 If the whole number is negative then the result is greater than the whole number, eg ½ × -2 = -1 > -2