Elements and Compounds

Metal and Alloys

Salt (Sodium Chloride)

Top Answer

As the molar mass of sodium chloride is 58.5 g/mol, there are 175.5 grams in 3 moles.

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023.3772 grams are there in four tenths moles of sodium chloride

0.40 moles NaCl (58.44 grams/1 mole NaCl) = 23 grams sodium chloride =================

0,40 moles of sodium chloride contain 23,376 g.

molecular formula for sodium chloride = NaClIf the mole (n) for NaCl = 5.3 moles, then the mole of sodium (Na) = 5.3 moles as well. 1 to 1 ratio mass = moles X molar mass m = 5.3 x 22.9 = 121.37 grams of sodium in 5.3 moles of sodium chloride

20.67 grams NaCl (1mol NaCl/58.44 g NaCl) = 0.3537 moles of sodium chloride

72.0 grams NaCl (1 mole NaCl/58.44 grams) = 1.2 moles of sodium chloride

The answer is 175,319 g.

The formula of sodium chloride is NaCl; therefore, the gram formula mass of sodium chloride is the sum of the gram atomic masses of sodium and chloride, or 58.443, to the justified number of significant digits. The number of gram formula masses in 23.376 grams is therefore 23.376/58.443 or 0.399998, to the justified number of significant digits.

There are 9.3504 grams of Sodium Chloride. Calculations: 0.160 mol NaCl (58.44g/mol) = 9.3504g NaCl

1.946 moles NaCl (58.44 grams/1 mole NaCl) = 113.7 grams sodium chloride ======================

10 moles of sodium chloride have 584,397 g.

Sodium chloride has a molar mass of about 58.5 g/mol. So multiply 8 moles by molar mass to get about 468 grams.

Multiply it by molar mass of NaCl. Answer is 117 grams

The answer is 2337,59 g NaCl.

A mole of an element or compound is 6.022 x 1023 (Avogadro's constant) molecules of that substance. This number is the number of molecules it takes for an amount of substance to have a mass in grams the same as its molecular mass: carbon has a molecular mass of 12, so 6.022 x 1023 (one mole) carbon atoms have a mass of 12 grams. The molecular mass of sodium is 23 (22.989) so one mole of sodium has a mass of 23 grams. Sodium chloride has a molecular mass of 58.44 so a mole of NaCl is 58.44 grams. One mole of sodium will make one mole of sodium chloride. Na + Cl => NaCl So four moles of sodium will make four moles of sodium chloride. 4Na + 4Cl => 4NaCl Four moles of NaCl has a mass of 4 x 58.44 = 233.76 grams.

0.40 moles of sodium chloride weighs 23.4g.

This question can be answered with the equation n = m ÷ M (where n is the number of mol's, m is te mass in grams and M is the Molar Mass of Sodium Chloride). Now, sodium chloride's molecular formula is written as, NaCl Now if we think of this formula as representing a ratio of elements within the compound, we can see that, NaCl : Cl = 1 mole of sodium chloride molecules : 1 mole of Chloride atoms So, as we know the mol ratio for this molecule, we can establish the mass of sodium in 11.7g of sodium chloride by first calculating the number of moles of Sodium chloride in 11.7g of the substance, so then moles = mass of sodium chloride ÷ Molar mass of sodium chloride = 11.7 ÷ 58.44277 = 0.20019584971759552122529442050745 moles (note that in stochiometry i personally prefer not to round numbers until the end of the question Now by applying this number to the mol ratio, we can calculate the number of moles of sodium in sodium chloride 1 mole of sodium chloride molecules : 1 mole of Chloride atoms =0.20019584971759552122529442050745 : 0.20019584971759552122529442050745 Now that we have established that the number of moles of of sodium in 11.7g of sodium chloride is 0.20019584971759552122529442050745 mol, the mass of sodium in 11.7g of sodium chloride can be calculated with the formula, m = n M = mass of sodium in 11.7g of sodium chloride = 0.20019584971759552122529442050745 X 23 = 4.6045045435046969881817716716713g (all decimal places)

The formula mass of sodium chloride, NaCl is 58.5 Mass of 0.40mol of NaCl = 0.40 x 58.5 = 23.4g

If 4,00 is 4,00 moles the answer is 233,759 g NaCl.

The mass is 467,52 g.

The answer is 0,017 moles.

The answer is 8,559.10-5 moles.

There are 10 moles present in 585 g of sodium chloride.

since molarity = (number of moles) / (volume of solution), the molarity of a solution with 2.3 moles of sodium chloride in 0.45 liters of water will be 5.11 moles.

For this you need the atomic (molecular) mass of NaCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaCl=58.5 grams10.0 grams NaCl / (58.5 grams) = .171 moles NaCl

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