Such numbers cannot be ordered in the manner suggested by the question because:
For every whole number there are integers, rational numbers, natural numbers, Irrational Numbers and real numbers that are bigger.
For every integer there are whole numbers, rational numbers, natural numbers, irrational numbers and real numbers that are bigger.
For every rational number there are whole numbers, integers, natural numbers, irrational numbers and real numbers that are bigger.
For every natural number there are whole numbers, integers, rational numbers, irrational numbers and real numbers that are bigger.
For every irrational number there are whole numbers, integers, rational numbers, natural numbers and real numbers that are bigger.
For every real number there are whole numbers, integers, rational numbers, natural numbers and irrational numbers that are bigger.
Each of these kinds of numbers form an infinite sets but the size of the sets is not the same. Georg Cantor showed that the cardinality of whole numbers, integers, rational numbers and natural number is the same order of infinity: aleph-null.
The cardinality of irrational numbers and real number is a bigger order of infinity: aleph-one.
Rational numbers are roots, decimals, fractions, and whole numbers. Bascially anything that can become a decimal. Irrational numbers are like pi. I'm pretty sure to be irrational, they have to repeat. Anyway, ordering them and comparing them means looking at them and seeing which is smallest and largest. Then you order them (smallest to largest or whatever it says).
If you allow non integers, then your smallest four-digit number would be .0001. If you only allow integers, then your smallest four-digit number would be 1000. Your largest four-digit number would be 9999.
There are an infinite number of rational numbers so it would be foolish to even try to list them.
You've come to the right place. The integers are: 2, 4, and 6
integers are a, a + 1 and a + 2. a + 5(a + 2) = -244 ie 6a = -234 so a = -39 and the other two are -40 and -41.
Rational numbers are roots, decimals, fractions, and whole numbers. Bascially anything that can become a decimal. Irrational numbers are like pi. I'm pretty sure to be irrational, they have to repeat. Anyway, ordering them and comparing them means looking at them and seeing which is smallest and largest. Then you order them (smallest to largest or whatever it says).
For x, which is the largest integer of nconsecutive positive integers of which the smallest is m:x = m + n - 1
Start with the largest and end with the smallest
If you allow non integers, then your smallest four-digit number would be .0001. If you only allow integers, then your smallest four-digit number would be 1000. Your largest four-digit number would be 9999.
There are an infinite number of rational numbers so it would be foolish to even try to list them.
5872345098234783904672083946728390752430689723409687298290843 theres your answer
You've come to the right place. The integers are: 2, 4, and 6
5, 6 and 34.
They are (14, 15, 16).
Let the smallest integer be 2n, the next integer is 2n + 2, and the largest one is 2n + 4. Then, we have:2n + (2n + 2) = (2n + 4) + 164n + 2 = 2n + 202n = 18 the smallest integer2n + 2 = 18 + 2 = 20 the next one2n + 4 = 18 + 4 = 22 the largest integerCheck
Divide the sum of the three consecutive odd integers by 3: -147 /3 = -49. The smallest of these integers will be two less than -49 and the largest will be two more than -49, so the three consecutive odd integers will be -47, -49, and -51.
x+(n+1)+3(n+2)= something then solve,