0.01 0.09 0.10 0.11
It depends on who you are trying to call.
Convert every octal digit into three binary digit: 0->000 1->001 2->010 3->011 4->100 5->101 6->110 7->111
Starting from the right, partition into triplets. Then convert each triplet of binaries into octal as follows: 000 = 0 001 = 1 010 = 2 011 = 3 100 = 4 101 = 5 110 = 6 111 = 7 That's it!
To convert a binary number to an octal number, you need to know how an octal number is represented in binary. It is like this: 0 = 000 4 = 100 1 = 001 5 = 101 2 = 010 6 = 110 3 = 011 7 = 111 As you can see, an octal number consists of 3 'bits' (either a 0 of a 1). Now, to convert a binary number to an octal number, you first have to group the binary digits into groups of 3 bits (starting from the right). Then, you convert every group of bits into octal numbers. This way you get your binary number into an octal one. For example: (1010100111010010)2 We group them into groups of 3 bits, starting from the right. 1 010 100 111 010 010 As you see, we have a single digit left. We must add 0's to make it a group of 3 bits. 001 010 100 111 010 010 Then we convert every group into an octal number, according to the table above. 001 = 1 010 = 2 100 = 4 111 = 7 010 = 2 010 = 2 And in this way, you converted a binary number into an octal one. (1010100111010010)2 = (124722)8
A002B07D16 -> binary A 1010 0 0000 0 0000 2 0010 B 1011 0 0000 7 0111 D 1101 A002B07D16 = 1010 0000 0000 0010 1011 0000 0111 11012 10 100 000 000 000 101 011 000 001 111 1012 -> octal 010 2 100 4 000 0 000 0 000 0 101 5 011 3 000 0 001 1 111 7 101 5 10 100 000 000 000 101 011 000 001 111 1012 = 240005301758 A002B07D16 = 24 000 530 1758
The smaller the value the closer it is to zero..003 < .01, therefore .003 is closer to zero.On a number line (not to scale):---(0)--(.001)-(.002)-(.003)-(.004)-(.005)-(.006)-(.007)-(.008)-(.009)-(.010)-(.011)Notice how .003 is closer to 0 than .010
Hot adjustment on the 1.3 engine is .009-.011 clearance on the Intakes, and .010-.012 clearance on the Exhaust valves
input: 76543210(8) output: 111 110 101 100 011 010 001 000(2)
Intake: .007 - .009 Exhaust: .009 - .011 Firing Order: 1-3-4-2
.010
.007 to .009 on the intake .009 to .011 on exhaust
001, 002, 003, 004, 005, 010, 011, 012, 013, 014, 015, 020, 021, 022 and 023.
It depends on who you are trying to call.
999 combination 001 002 003 004 005 006 007 008 009 010 011 012 013 014 015 016 017 018 019 until 099 then change all the front 0 to 1-9 and if you dont believe me think of a combination and try it im 11 years old
Each digit represents 3 bits. 0 = 000 1 = 001 2 = 010 3 = 011 4 = 100 5 = 101 6 = 110 7 = 111
Convert every octal digit into three binary digit: 0->000 1->001 2->010 3->011 4->100 5->101 6->110 7->111
011001.0011102 = 31.168 Simply group the bits in groups of three... 011 001 . 001 110 ... and convert each group to octal.