Fe3O4 is FeO.Fe2O3 and it is always -2 for Oxygen and +2 for iron (in FeO) and +3 for iron (Fe2O3)
The formula for iron using the highest oxidation number is Fe2O3, which is iron(III) oxide. In this compound, iron is in the +3 oxidation state.
This is iron II, III oxide and features iron in both the 2+ and 3+ oxidation states.
The oxidation number of iron in the brown ring complex is +2. This complex is [Fe(H2O)5NO]2+ where the iron atom is in the +2 oxidation state.
The oxidation number of Fe in FeO (iron oxide) is +2. This is because oxygen typically has an oxidation number of -2, and in a neutral compound like FeO, the oxidation numbers must balance out to zero.
study island answer is +3 -2
The formula for iron using the highest oxidation number is Fe2O3, which is iron(III) oxide. In this compound, iron is in the +3 oxidation state.
This is iron II, III oxide and features iron in both the 2+ and 3+ oxidation states.
The oxidation number of iron in the brown ring complex is +2. This complex is [Fe(H2O)5NO]2+ where the iron atom is in the +2 oxidation state.
The oxidation number of Fe in FeO (iron oxide) is +2. This is because oxygen typically has an oxidation number of -2, and in a neutral compound like FeO, the oxidation numbers must balance out to zero.
study island answer is +3 -2
The oxidation state of iron in iron (III) compounds is +3. This means that each iron atom in these compounds has lost 3 electrons.
In Fe2O3, iron (Fe) has an oxidation number of +3, and oxygen (O) has an oxidation number of -2. Iron's oxidation number is determined by balancing the overall charge of the compound based on the known oxidation number of oxygen.
The oxidation number of iron is +2 (Fe2+), and the oxidation number of oxygen is -2 (O2-). In iron(II) oxide (Fe2O3), which has two iron ions and three oxygen ions, the overall charge must balance to zero, so the oxidation number of iron is +3.
The given chemical equation represents a redox reaction, specifically a reduction-oxidation reaction. It involves the transfer of electrons between iron (Fe) and hydrogen (H) to form different compounds.
The oxidation number of iron in sodium nitroprusside is +2. This is because the overall compound has a neutral charge, and since there are 5 cyanide ions each with a -1 charge, the iron must have a +2 oxidation state to balance the charges.
The oxidation number change for the iron atom in a reaction is from Fe^0 (elemental form) to Fe^2+ or Fe^3+ (ionic form). This represents an oxidation of the iron atom, as it loses electrons and increases its oxidation state.
The oxidation number of iron in ferrousofericoxide (Fe3O4) is a combination of Fe(II) and Fe(III) ions. The Fe(II) ions have an oxidation number of +2, while the Fe(III) ions have an oxidation number of +3. Each formula unit of Fe3O4 contains two Fe(III) ions and one Fe(II) ion, resulting in an average oxidation number of +2.67 for iron in this compound.