pOH = -log[OH-] = -log(5*10^-3) = 2.3
pH = 14 - pOH = 14.0 - 2.3 = 11.7 (at 25 oC)
The pH of a solution can be calculated using the formula: pH = -log[OH-]. Therefore, for a solution with [OH-] concentration of 10-12 M, the pH would be 12.
The pH of a Ca(OH)2 solution is around 12.5, making it basic.
A solution with a pH of 5 has an OH- concentration of 1x10^-9 mol/L. To find a solution with 1000 times higher OH- concentration, we multiply 1x10^-9 by 1000 to get 1x10^-6 mol/L. The pH of this solution with a higher OH- concentration would be 8.
A solution with a greater concentration of H+ ions has a lower pH value, indicating an acidic solution, while a solution with a greater concentration of OH- ions has a higher pH value, indicating a basic solution. The concentration of H+ and OH- ions in a solution are inversely related in water, following the equation: [H+][OH-] = 10^-14 at 25°C.
The pH of a neutral solution with equal concentrations of H+ and OH- ions is 7. This is because the concentration of H+ ions equals the concentration of OH- ions in a neutral solution, resulting in a pH of 7.
The pH of a solution can be calculated using the formula: pH = -log[OH-]. Therefore, for a solution with [OH-] concentration of 10-12 M, the pH would be 12.
The pH of a Ca(OH)2 solution is around 12.5, making it basic.
A solution with a pH of 5 has an OH- concentration of 1x10^-9 mol/L. To find a solution with 1000 times higher OH- concentration, we multiply 1x10^-9 by 1000 to get 1x10^-6 mol/L. The pH of this solution with a higher OH- concentration would be 8.
The pH of a solution can be calculated using the formula pH = 14 - pOH. Given that the pOH is 3.31, we can subtract this value from 14 to find the pH. In this case, the pH of the solution would be approximately 10.69.
A solution with a greater concentration of H+ ions has a lower pH value, indicating an acidic solution, while a solution with a greater concentration of OH- ions has a higher pH value, indicating a basic solution. The concentration of H+ and OH- ions in a solution are inversely related in water, following the equation: [H+][OH-] = 10^-14 at 25°C.
The pH of a neutral solution with equal concentrations of H+ and OH- ions is 7. This is because the concentration of H+ ions equals the concentration of OH- ions in a neutral solution, resulting in a pH of 7.
The concentration of H+ or OH-.
The pH of a solution can be calculated using the formula pH = 14 - (-log[OH-]). Using the given concentration of 2.3 x 10^-5 M for OH-, the pH would be approximately 9.64.
To find the concentration of hydroxide ions ([OH-]) in a solution when the pH is 4.0, you can use the formula pH + pOH = 14. Since the pH is 4.0, the pOH would be 14 - 4 = 10. To convert pOH to [OH-] concentration, use the formula [OH-] = 10^(-pOH). Thus, [OH-] = 10^(-10) = 1 x 10^(-10) M.
-log(10^-4 M) = 4 14 - 4 = 10 pH
The concentration of H+ ions in a solution determines its acidity; the higher the concentration of H+ ions, the lower the pH. The concentration of OH- ions in a solution determines its alkalinity; the higher the concentration of OH- ions, the higher the pH. pH is a logarithmic scale that represents the concentration of H+ ions in a solution.
The pH of a 0.0110 M solution of Ba(OH)2 can be calculated by finding the hydroxide ion concentration, which is double the concentration of the Ba(OH)2 solution. Therefore, [OH-] = 2 * 0.0110 M = 0.0220 M. From this, you can calculate the pOH using the formula -log[OH-], and then convert pOH to pH using the relation pH + pOH = 14.