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100(23.9/30.3) = 78.9 % Ni, to the justified number of significant digits.

100(6.4/30.3) = 21 % O, to the justified number of significant digits.

Fewer significant digits are given for the oxygen percentage because one of its input data, 6.4, has only two significant digits.

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12y ago
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13y ago

Easy to do on your own.

Ni=79%

O=21%

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6y ago

78.64% Ni

21.36% O

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Q: What is the percent composition of NiO if a sample of NiO with a mass of 41.9 g contains 33.1 g Ni and 8.8 g O?
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