264.0625 or (65÷4)2 = 8.252 = 264
Do you mean the width? If so then let the width be x: 2(length+width) = perimeter 2(18+x) = 65 36+2x = 65 2x = 65-36 2x = 29 x = 14.5 width = 14.5 units in length Check: 18+18+14.5+14.5 = 65
if the primeter of a regular pentagon is 65 cm.find its length?
16.25+16.25+16.25+16.25 = 65 Answer: 65cm
65 yards
264.0625 or (65÷4)2 = 8.252 = 264
Do you mean the width? If so then let the width be x: 2(length+width) = perimeter 2(18+x) = 65 36+2x = 65 2x = 65-36 2x = 29 x = 14.5 width = 14.5 units in length Check: 18+18+14.5+14.5 = 65
if the primeter of a regular pentagon is 65 cm.find its length?
16.25+16.25+16.25+16.25 = 65 Answer: 65cm
65 yards
With a perimeter of 36, and a known width of 5, that means the length is 13. This makes the area 65.Perimeter = (2 x Length) + (2 x Width)Width = [Perimeter - (2 x Length)]/2= [36 -(2 x 13)]/2= (36 - 26)/2= 10/2= 5 inchesArea = Length x Width= 13 x 5= 65 square inches
65, 78 and 91 units.
Let W be any number between 0 and 32.5 (both end points excluded.) Let L = 65 - W Then the garden with length L and width W will have a perimeter of 2*(L+W) = 2*(65 - W + W) = 2*65 = 130 Since W can take an infinite number of values, there are an infinite number of possible solutions.
There seems to be a degree of difficulty about perimeter, which is just the measurement of the outline of the figure. It appears that your figure is a rectangle so the perimeter is merely twice (the sum of length and width, ie 150 units). If length exceeds width by 20 then length is 85 and width is 65.
A regular pentagon is equilateral(all sides are equal) 5*13 = 65 cm
The area of a hexagon with an edge length of 5 is about 65 units2. If you mean the perimeter is 5, then the area will be 0.833 units2
The perimeter of a square is four times the length of one side. Since the length of the side is not given here, you have to figure that out first. Note that the area of a square is the square (the second power) of the length of one side.