The area of a rectangle is not enough information to determine its shape (thin and narrow or fat and short) and therefore its perimeter.
You cannot find the perimeter unless the rectangle is a regular rectangle (a square) in which case the perimeter is 4 times the square root of the area. With just the area the shape of the rectangle could be any number of shapes with different perimeter, for example, imagine 6 square units 1cm by 1cm arranged in a 1*6 configuration to give a long thin rectangle, the perimeter would be 6+6+1+1=14cm, the same 6 arranged in a 3*2 rectangle would have the same area, but a perimeter of 3+3+2+2=10cm, for this reason a rectangle's perimeter cannot be determined from the area alone.
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
The sides of the rectangle are 3 times square root of 5 and 5 times square root of 26 The perimeter of the quadrilateral is approximately 64 units
perimeter of a square = 4 * root of the area. Perimeter = 4 * root 25 = 4 * 5 = 20 ft
Perimeter = 4 times the square root of the area.
The perimeter of a rectangle cannot be calculated by just knowing the area unless the rectangle is a square. In which case the perimeter will be 4 x square root of the area.
There is no single answer to that The rectangle could be 0.9 by 1, giving a perimeter of 2x(0.9+1)=3.8 Or it could be 0.45 by 2, giving it a perimeter of 2x(0.45+2)=4.9 The minimum perimeter is when it is a square. The square root of 0.9 is approx 0.94868, so the perimeter would be approx 3.7947
You cannot find the perimeter unless the rectangle is a regular rectangle (a square) in which case the perimeter is 4 times the square root of the area. With just the area the shape of the rectangle could be any number of shapes with different perimeter, for example, imagine 6 square units 1cm by 1cm arranged in a 1*6 configuration to give a long thin rectangle, the perimeter would be 6+6+1+1=14cm, the same 6 arranged in a 3*2 rectangle would have the same area, but a perimeter of 3+3+2+2=10cm, for this reason a rectangle's perimeter cannot be determined from the area alone.
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
Square the diagonal and take away the square of width, this gives you the square of the other side. Add the square root of the two sides and multiply by two.
For a given area a circle has least perimeter. eg Let area = 100 sq cms. For the square or rectangle the perimeter = 40 cms For the circle the radius is square root of 100/3.1416 = 5.64 and the circumference = 2 x radius x 3.1416 = 35.44 cms
The sides of the rectangle are 3 times square root of 5 and 5 times square root of 26 The perimeter of the quadrilateral is approximately 64 units
perimeter of a square = 4 * root of the area. Perimeter = 4 * root 25 = 4 * 5 = 20 ft
Assuming that you want to minimise the perimeter, then use a square. Its side length is, of course, given by the square root of the area.
Minimum is when the figure is a square, in this case the perimeters 4 times the square root of 48. There is no maximum, i.e., you can make the perimeter as large as you like.
Perimeter = 4 times the square root of the area.
Depends on the shape. A square's perimeter would be 4 root 9 ie 12 cm, but you could have a 9 x 1 rectangle which would have a perimeter of 20 cm etc etc