The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
y=3x-3
Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
Point-slope form is written as: y-y1=m(x-x1), where (x1, y1) is a point on the line and m is the slope (hence the name, point-slope form).
Point slope form is standard form. To change point slope form into general form, simply multiply both sides by the denominator of the slope, and move everything onto one side.
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Point: (2, -1) Slope: -5 Equation: y = -5x+9
y-1 = 3(x - 2)
If you mean a point of: (2,1) then the equation works out as y = 3x-5
y = 2x + 1
Slope: -3 Point: (4, -5) Equation: y = -3x+7
y=2x+13
y=3x-3
Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7
y = 2x - 1
y=2x+1
The answe iss..... 6