The power factor (cosine of phase angle) of pure inductor is zero because the phase angle between current and voltage is 90 degrees .If the value is substituted in the formula It will be zero.
The power factor for any reactive load, inductive or capacitive, is the cosine of the phase angle between voltage and current. It is also the ratio of volt-amps over watts. We call it a lagging power factor if it is inductive, and a leading power factor if it is capacitive.
Incandescent lamps are nearly pure resistive loads with a power factor of 1
A resistor doesn't have a power factor. However, if a circuit is pure resistance in nature the power factor will be one when a voltage is applied and a current flows in the circuit. The power factor is a measure of the relative phases of the current and voltage in a circuit.
With a pure resistive load the Power Factor should be 1.
The power factor measures the phase difference between a current and a voltage waveform. Power factor ranges from zero to one. A power factor of 1 is for a pure resistive load. Power factor decreases for loads like motors with high inductance. Power factor comes into play when determining the watts used by a device. Watts = Volts x Amps x PF. So ideally for efficiencies sake, you want to keep the PF as close to one as possible.
The question makes no sense. It asks why a pure inductive load is used ... instead of a pure inductive load. Please restate the question.
Pure inductors consume and produce power, just like other reactive devices. The difference is that the current is not in phase with the voltage, resulting in the waveform of the power being oscillating about zero, with a net mean power of zero. In this "pure" case, the power factor is zero, but that does not mean there is no power - its just that the power "reading" is unsophisticated and not compensating for power factor.
1
Incandescent lamps are nearly pure resistive loads with a power factor of 1
ratio between true power and apparent power is called the power factor for a circuit Power factor =true power/apparent power also we conclude PF=power dissipated / actual power in pure resistive circuit if total resistance is made zero power factor will be zero
A resistor doesn't have a power factor. However, if a circuit is pure resistance in nature the power factor will be one when a voltage is applied and a current flows in the circuit. The power factor is a measure of the relative phases of the current and voltage in a circuit.
0. Power factor has to do with the amount of real power. if you have a purely capacitive load, there is no real power flow, thus pf = 0. For purely resistive load, power factor will be 1.0.
Power factor does not apply to a resistive circuit. Just the current will follow the voltage (in phase)
With a pure resistive load the Power Factor should be 1.
A pure resistive load always has a power factor of one. This is because the current and voltage waveforms are in phase in an AC circuit.
Angle between v and i is 90 deg so, cos 90 = 0 Same for pure capacitor
Watts = Volts x Amps x Power Factor. To answer your question requires that the Power Factor be know. The Power Factor ranges from zero to one and is one for a pure resistive load. If your device is resistive the answer is 1500 watts.
Watts = Volts x Amps x Power Factor To make your calculation you need to plug-in the Voltage and Power factor. The Power Factor is a value from zero to one with one being a pure resistive load.