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What is the probability of flipping 25 heads in a row?


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Answered 2010-02-02 19:39:23

The best way to think about this is the following way:

What is the probability of flipping heads once?

1/2

What is the probability of flipping heads twice?

1/4 (1/2 * 1/2)

Using this we can derive the equation to find the probability of flipping heads any number of times. 1/2n

Using this we plug in 25 for n and get

1/225 or as a decimal 2.98023224 x 10-8

or as odds 1:33,554,432

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The probability is 25%. The probability of flipping a coin once and getting heads is 50%. In your example, you get heads twice -- over the course of 2 flips. So there are two 50% probabilities that you need to combine to get the probability for getting two heads in two flips. So turn 50% into a decimal --> 0.5 Multiply the two 50% probabilities together --> 0.5 x 0.5 = 0.25. Therefore, 0.25 or 25% is the probability of flipping a coin twice and getting heads both times.


We have no way of knowing the probability of any given person flipping any given coin at any given time. But for any two flips of an honest coin, the probability that both are tails is 25% . (1/4, or 3 to 1 against)


The probability is 0.25.Look at it this way--if you toss a coin twice, there are four equally-probable outcomes:tails, tailstails, headsheads, tailsheads, headsSo the probability of heads twice in a row is one in four, or 25%.the chance of tossing heads is 1/2 (50%) The chance of tossing the next heads is 1/2 (50%) 1/2 x 1/2 = 1/4 (25%)


The probability of getting all tails is 1/25 = 1/32


The probability that both coins are heads is the probability of one coin landing heads multiplied by the probability of the second coin landing heads: (.5) * (.5) = .25 or (1/2) * (1/2) = 1/4


75% is not correct. The odds of flipping 4 independent coins is the same as flipping one coin 4 times. The number of outcomes of 4 flips is 2^4 or 16. The number of ways to exactly get 3 Heads is 4 (THHH, HTHH, HHTH, HHHT) so your chance of flipping 3 heas is 4/16 or 25%. If you include the occurance that produced 4 of 4 Heads, then you get 5/16 or 31.25%.



A die has six sides, so the probability of rolling an even number is 1 in 2, or 50-50. A coin has two sides, so the probability of flipping the coin and getting heads is 1 in 2, or 50-50. The probability that both will happen together is the one in two OF one in two, or one in FOUR chance that both will happen. So, the probability is 25%.


The probability of one event or the other occurring is the probability of one plus the probability of the other. The probability of getting 3 heads is the probability of 3 heads (1/23) multiplied by the probability of 4 tails (1/24) multiplied by the number of possible ways this could happen. This is 7c3 or 35. Thus the probability of 3 heads is 0.2734375. The probability of 2 tails is the probability of 2 tails (1/22) multiplied by the probability of 5 heads (1/25) multiplied by the number of ways this could happen. That is 7c5 or 21. Thus the probability of 2 tails is 0.1640625 The probability of one or the other is the sum of their probabilities: 0.1640625 + 0.2734375 = 0.4375 Thus the probability of getting 3 heads or 2 tails is 0.4375.


No, when you toss a coin there is a 50 percent chance it will land heads up.


These are all independent events (flipping a coin will not affect the probability of drawing a Jack) so you can get the probability of all events occurring by multiplying together the probabilities of each event occurring. In other words: P (4 or 6, 2 heads, Jack) = P(4 or 6) * P(2 Heads) * P(Jack) Now we need to look at each probability separately. Remember that: Probability = Successful Outcomes / (Successful Outcomes + Unsuccessful Outcomes) In the case of rolling a die, a successful outcome (as defined in the problem) is rolling a 4 or 6. An unsuccessful outcome is everything else (1, 2, 3, or 5). Using the formula above then: Probability (4 or 6) = 2/6 = .33 Figuring out the probability of rolling two heads is slightly different because we are talking about two flips not one. In this case we have to go back to our original formula for multiple events. Probability (2 Heads) = Prob(Head) * Prob(Head) Since we know a coin-toss has a 1/2 chance of being heads or tails: Probability (2 Heads) = .5 * .5 = .25 Finally, in the case of picking up a card from a deck, a successful outcome (as defined in the problem) is picking a Jack. There are 4 Jacks in a standard deck so there are 4 possibilities of a successful outcome. There are 48 cards in a stardard deck that are not Jacks. Therefore: Probability (Jack) = 4/52 = .077 Now we can plug these values into our combination formula to get our answer. P (4 or 6, 2 heads, Jack) = P(4 or 6) * P(2 Heads) * P(Jack) P (4 or 6, 2 heads, Jack) = .33 * .25 * .077 = .00635 There is a .635% chance of rolling a 4 or 6, flipping a heads twice, AND drawing a Jack.


If you are talking about coins, 25% If you are talking about genetics, then it is less than 1%.



If you flip a coin twice, there are four possible results:H HH TT HT T.The result you're interested in is one of the four possibilities.So its probability is 1/4 = 25% .


The probability of heads on the first flip is 50%.The probability of heads on the second flip is 50%.The probability of both is (50% x 50%) = 25% .=========================================Another way to look at it:Two tosses can come up in four different ways:H HH TT HT TOnly one of these . . . H H . . . counts as success.1 out of 4 = 25% .



25% or 0.25 Probability of one tail is 0.50. Since two tails are independent events, the probability is 0.5 x 0.5 = 0.25


lets get some facts odds of head on 1 coin 50% or evens odds of no head 50% or evens the possible results vary from 1 coin to 2 coins. 1 coin has 2 results heads or tails 2 coins have 4 results. heads heads, tails tails, tails heads, heads tails. each outcome has a probability of 25%. for the question we remove the heads and tail probability and we have 2 outcomes with heads and one without. so 2 to 1 chance or 33.3333 recuring chance.


There are four different ways that two coins can land: T T T H H T H H. Only one of them is two heads, so if the coins are fair, then the probability is 1/4 = 25% .


For 3 coin flips: 87% chance of getting heads at least once 25% chance of getting heads twice 13% chance of getting heads all three times


The probability of tossing a coin twice and getting tails both times is 1 in 4, or 25%. If you have already tossed a coin and had it land on tails, the probability that it will land on tails again the next time you toss it is 50%.


Since the chance of lanind on either heads or tails in 50% or 1/2 every time the coin is flipped, all you have to do is multiply 1/2 x 1/2 because you are flipping twice. That is, 1/2 chance you will get heads the first time, and then 1/2 you will tails the next time. The chances never change on a coin. So your answer is 1/4 or 25% chance of that even occuring.


Two ways to think about it: 1: 25% both heads 50% one of each 25% both tails -or- 2: 25% heads/heads 25% heads/tails 25% tails/heads 25% tails/tails


This is a good bet to take. Your expected payout is 0.5 each round of the 2 tosses. The possible outcomes from 2 tosses: HT, HH, TT, TH. The probability that heads comes up is 3 in 4 (.75). The probability that heads does not come up is 1 in 4 (.25). Your expected payout is: (2 * .75) + (-4 * .25) = 1.5 - 1 = 0.5


The total probability of something happening plus the probability of that same thing not happening is 1, or 100 % → probability of not happening = 1 - 0.25 = 0.75 or 100 % - 25 % = 75 %