Math and Arithmetic

Statistics

Probability

Top Answer

The probability is 25%.

The probability of flipping a coin once and getting heads is 50%. In your example, you get heads twice -- over the course of 2 flips. So there are two 50% probabilities that you need to combine to get the probability for getting two heads in two flips.

So turn 50% into a decimal --> 0.5

Multiply the two 50% probabilities together --> 0.5 x 0.5 = 0.25.

Therefore, 0.25 or 25% is the probability of flipping a coin twice and getting heads both times.

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0The probability of this is 50%. 2/4

Well, you have 24 possibilities, and you can get heads 6 ways, so it is 1/4.

Your question is a bit difficult to understand. I will rephrase it as follows: What is the probability of getting a head if a coin is flipped once? p = 0.5 What is the probability of getting 2 heads if a coin is flipped twice = The possible events are HT, TH, HH, TT amd all are equally likely. So the probability of HH is 0.25. What is the probability of getting at least on head if the coin is flipped twice. Of the possible events listed above, HT, TH and HH would satisfy the condition of one or more heads, so the probability is 3 x 0.25 = 0.75 or 3/4. Also, since the probability of TT is 0.25, and the probability of all events must sum to 1, then we calculate the probability of one or more heads to be 1-0.25 = 0.75

The best way to think about this is the following way: What is the probability of flipping heads once? 1/2 What is the probability of flipping heads twice? 1/4 (1/2 * 1/2) Using this we can derive the equation to find the probability of flipping heads any number of times. 1/2n Using this we plug in 25 for n and get 1/225 or as a decimal 2.98023224 x 10-8 or as odds 1:33,554,432

The answer is 1/2 , assuming the coin is fair.

The probability is 1/2 because the second outcome has no affect on the first outcome.

20!/(18!*2!) * (1/2)^20 = 190/1048576 = 0.000181198... So less than 1 in 5000.

If the coin is not biased, the answer is 0.375

If you flip a coin twice, there are four possible results:H HH TT HT T.The result you're interested in is one of the four possibilities.So its probability is 1/4 = 25% .

For 3 coin flips: 87% chance of getting heads at least once 25% chance of getting heads twice 13% chance of getting heads all three times

The probability of landing on heads each time a fair coin is flipped, is 1/2.Assuming that the question was supposed to be:"What is the probability of landing on heads twice in a row?"To calculate compound probabilities like this, we first have to work out the probability of landing on heads each time, and then multiply these two probabilities to get a compound probability.1/2 x 1/2 = 1/4So the probability of landing on heads twice in a row = 1/4 (for a fair coin)

What is the chance of it landing on heads twice in a row?

The probability is 0.25.Look at it this way--if you toss a coin twice, there are four equally-probable outcomes:tails, tailstails, headsheads, tailsheads, headsSo the probability of heads twice in a row is one in four, or 25%.the chance of tossing heads is 1/2 (50%) The chance of tossing the next heads is 1/2 (50%) 1/2 x 1/2 = 1/4 (25%)

One in four. 1:4. The probability of getting heads when a fair coin is tossed is: P(H) = 1/2. The probability of getting heads on a second toss is: P(H) = 1/2, this result is independent of the result of the first toss. The probability of having both events happen (heads on the first and heads on the second toss) is: P(H1UH2) = (1/2)∙(1/2) = 1/4 = 0.25 = 0.25%

The sample space is HH, HT, TH, HH. Since the HH combination can occur once out of four times, the probability that if a coin is flipped twice the probability that both will be heads is 1/4 or 0.25.

P(tail) is 0.5. You want P(tail) AND P(tail) = 0.5 * 0.5 = 0.25 or 1/4.

The probability to get heads once is 1/2 as the coin is fair The probability to get heads twice is 1/2x1/2 The probability to get heads three times is 1/2x1/2x1/2 The probability to get tails once is 1/2 The probability to get tails 5 times is (1/2)5 So the probability to get 3 heads when the coin is tossed 8 times is (1/2)3(1/2)5=(1/2)8 = 1/256 If you read carefully you'll understand that 3 heads and 5 tails has the same probability than any other outcome = 1/256 As the coin is fair, each side has the same probability to appear So the probability to get 3 heads and 5 tails is the same as getting for instance 8 heads or 8 tails or 1 tails and 7 heads, and so on

'At least' means equal to or greater than. This meaning is not restricted to maths; it is one of the common everyday meanings of the phrase.So if you have a question which, for example, tells you to calculate the probability of getting at least one head when a coin is flipped twice then it means:What is the probability of getting one or more heads when a coin is flipped twice.

The answer depends on how many times the coin is tossed. The probability is zero if the coin is tossed only once! Making some assumptions and rewording your question as "If I toss a fair coin twice, what is the probability it comes up heads both times" then the probability of it being heads on any given toss is 0.5, and the probability of it being heads on both tosses is 0.5 x 0.5 = 0.25. If you toss it three times and want to know what the probability of it being heads exactly twice is, then the calculation is more complicated, but it comes out to 0.375.

Your question is slightly vague, so I will pose a more defined question: What is the probability of 3 coin tosses resulting in heads exactly twice? This is a pretty easy question to answer. The three possible (winning) outcomes are: 1. Heads, Heads, Tails. 2. Heads, Tails, Heads. 3. Tails, Heads, Heads. If we look at the possible combination of other (losing) outcomes, we can easily determine the probability: 4. Heads, Heads, Heads. 5. Tails, Tails, Heads. 6. Tails, Heads, Tails. 7. Heads, Tails, Tails. 8. Tails, Tails, Tails. This means that to throw heads twice in 3 flips, we have a 3 in 8 chance. This is because there are 3 winning possibilities out of a total of 8 winning and losing possibilities.

the only combination which does not produce heads at least once it tails twice. the odds of getting tails twice is 0.5*0.5=0.25 so the odds for getting heads at least once is 1-0.25=0.75 or 75% or 3/4.

4C2(1/2)4 = 6/16 = 3/8

The probability of tossing a coin twice and getting tails both times is 1 in 4, or 25%. If you have already tossed a coin and had it land on tails, the probability that it will land on tails again the next time you toss it is 50%.

Simple question, difficult answer. It depends on how many times you want the penny to land on heads. The probability of a penny landing on heads once is 1 in 2. For it to land on heads twice is 1 in 4, for three times it is 1 in 8, and so on and so forth.

These are all independent events (flipping a coin will not affect the probability of drawing a Jack) so you can get the probability of all events occurring by multiplying together the probabilities of each event occurring. In other words: P (4 or 6, 2 heads, Jack) = P(4 or 6) * P(2 Heads) * P(Jack) Now we need to look at each probability separately. Remember that: Probability = Successful Outcomes / (Successful Outcomes + Unsuccessful Outcomes) In the case of rolling a die, a successful outcome (as defined in the problem) is rolling a 4 or 6. An unsuccessful outcome is everything else (1, 2, 3, or 5). Using the formula above then: Probability (4 or 6) = 2/6 = .33 Figuring out the probability of rolling two heads is slightly different because we are talking about two flips not one. In this case we have to go back to our original formula for multiple events. Probability (2 Heads) = Prob(Head) * Prob(Head) Since we know a coin-toss has a 1/2 chance of being heads or tails: Probability (2 Heads) = .5 * .5 = .25 Finally, in the case of picking up a card from a deck, a successful outcome (as defined in the problem) is picking a Jack. There are 4 Jacks in a standard deck so there are 4 possibilities of a successful outcome. There are 48 cards in a stardard deck that are not Jacks. Therefore: Probability (Jack) = 4/52 = .077 Now we can plug these values into our combination formula to get our answer. P (4 or 6, 2 heads, Jack) = P(4 or 6) * P(2 Heads) * P(Jack) P (4 or 6, 2 heads, Jack) = .33 * .25 * .077 = .00635 There is a .635% chance of rolling a 4 or 6, flipping a heads twice, AND drawing a Jack.

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