Math and Arithmetic

Statistics

Probability

Top Answer

Sample space for two coins tossed is:

HH

HT

TH

TT

Therefore at most one head is HT TH TT or 3/4 or 0.75.

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03/8 * * * * * That is the probability of getting EXACTLY 1H. The prob of getting one (or more) head is 7/8

is it 50% or 100% dang, i just confused myself. what if you toss 3 coins all at the same time... what's the probability of getting a head then, is it > 100% ? Doh!

The probability is 50-50.

obviously it is a 50-50 chance

1/2 or 50% (1/8 prob of 0H + 3/8 prob of 1H)

the probability of getting one head and one tail on three flips of a coin is 1/9

Assuming that it is a fair coin, the probability is 0.9990

When two fair coins are tossed, you have the following possible outcomes: HH, HT, TH, TT. So, at most implies that you get either i) zero heads or ii) one head. From the possible outcomes we see that 3 times we satisify the outcome. Thus, probability of at most one head is 3/4.

By tossing two coins the possible outcomes are:H & HH & TT & HT & TThus the probability of getting exactly 1 head is 2 out 4 or 50%. If the question was what is the probability of getting at least 1 head then the probability is 3 out of 4 or 75%

At least two heads with two coins? You can't get more.There are 4 different outcomes:tail-tail, head-tail, tail-head and head-head.You can use one out of four - which gives us the probability 1/4 = 0.25 = 25%

Just one head = 2/4 = 1/2

Probability is the likelihood that something will occur. If you subtract it from 1, we get the likelihood (or probability) that it will not occur. If a coin is tossed and rolls heads 6 times, the (empirical) probability of obtaining a head is 6/10 or .6. 1-.6 =.4 is the empirical probability (or likelihood) of not getting a head.

The probability of getting 8 heads out of 10 tosses is (10C8)(1/2)^8 (1/2)^2 = 45 / 1024 = 0.0439. It is assumed that the probability of getting a head in a single toss is 1/2. 10C8 = 10 x 9 / 1 x 2 = 45

i don't know figure it out yourself... >_> * * * * * Pr(at most 1 H) = Pr(0 H) + Pr(1 H) = 1/16 + 4/16 = 5/16

The probability of getting a head on each occasion if a coin is tossed five times is equal to 1/2 x 1/2 x 1/2 x 1/2 x 1/2 (that is, 1/25) = 1/32 or one in thirty-two. The probability of getting a head on the fifth toss is 1/2. All other tosses are independent of the fifth toss. The probability of getting at least one head when tossing the coin 5 times: Since there are 32 possible combinations and only one of those combinations is all tails you could expect to toss a combination with a head 31/32 times. The probability is 0.96875.

lets get some facts odds of head on 1 coin 50% or evens odds of no head 50% or evens the possible results vary from 1 coin to 2 coins. 1 coin has 2 results heads or tails 2 coins have 4 results. heads heads, tails tails, tails heads, heads tails. each outcome has a probability of 25%. for the question we remove the heads and tail probability and we have 2 outcomes with heads and one without. so 2 to 1 chance or 33.3333 recuring chance.

75%. There are 3 possible ways of getting at least one tail from 2 tosses from a coin:Tail & Tail orHead & Tail orTail & HeadEach of these individual outcomes has a probability of 25% (e.g. the probability of getting a tail and then another tail is 25%). Adding the possible outcomes together gives you a total of 75%.

(1/2)^3 = 1/8th Since the initial probability (assuming independence) of getting a head in a single toss is one half (1/2) we just cube this probability because of the number of events we are performing. So if you were to try to calculate the probability of a coin being tossed 6 times it would be one half to the 6th power which is 1/64.

When we toss a coin getting head or tail have equal probability of 50% - that is, out of the two possible outcomes getting the specified one becomes 1/2 probability. When we toss three coins, the probability of getting all the coins showing tails is given by (1/2) * (1/2) * (1/2) equal to 1/8 or 12.5 % chance. Alikban

0.5, 1/2, 50% The probability for heads versus tails does not change based on the amount of times the coin is tossed. It will always be a 50% chance.

The probability of 2 coins both landing on heads or both landing on tails is 1/2 because there are 4 possible outcomes. Head, head. Head, tails. Tails, tails. Tails, heads. Tails, heads is different from heads, tails for reasons I am unsure of.

Probability of the first head = 0.5Probability of the second head = 0.5Probability of the tail on the 3rd toss = 0.5Probability of the correct 3-toss sequence = (0.5 x 0.5 x 0.5) = 1/8 = 0.125 = 12.5%

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