A die normally has six sides with the numbers 1 to 6 on them, so any roll will be less than 10 and thus the probability of getting less than 10 with a die is 1.
With two normal dice, the sum of the digits on the dice added together ranges from 2 to 12 and the probability of getting less than 10 is the same as 1 minus the probability of getting 10 or more.
There are 36 ways the two dice can fall and 10 can be achieved in 3 ways (4&6, 5&5, 6&4), 11 can be achieved in 2 ways (5&6, 6&5) and 12 in 1 way (6&6).
Thus the probability of getting 10 or more with 2 dice is (3+2+1)/36 = 6/36 = 1/6
So the probability of getting less than 10 is 1-1/6 = 5/6
When you roll 2 dice, the number of possible outcomes is 6x6 =36. From these 36 outcomes 3 are a 2 or 3 [(1,1), (1,2), (2,1)]. So the probability of getting a 2 or 3 is: P(2 or 3) = 3/36 = 1/12 = 0.08333... ≈ 8.3%
If we are thinking of getting a '6', here are the odds. Wth one dice, its 1 in 6. So,with two dice its 1 in 216 with three dice its 1 in 7776 with four dice its 1 in 279936 with five dice its a huge 1 in 10077696
It is 6/36 = 1/6.
I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.
Assuming that a dice roll is purely random, there is a 1 in 6 probability of landing on any number. Since the second roll depends on the probability of the first, they factor together: First Roll: 1/6 Second Roll: (1/6)(1/6) = 1/36 If you were rolling both dice at once, however, the math would be completely different.
It is 5/6.
One.
The probability is certain or 1. The max you can roll is 12 so it is certain the sum will be less than 13.
33,33333...%
1:6
1 out of 6 times,or 16.67% probability.
The probability is 5/36.
In one roll the probability is 1/36.
It is 2/6 = 1/3
The probability of getting a 7 on one roll of a die is zero.If you meant to ask about two dice, the probability is 6 in 36, or 1 in 6.
The probability of getting 11 with one throw of 2 dice is 1/6*1/6*2 = 1/18 So the probability of not getting 11 with 1 throw of the dice is 17/18. Tossing the dice 54 times, the probability of not getting 11 54 times is (17/18)54 = 0.0456... So the probability of at least 1 roll of 11 is 1 - 0.0456 = 0.954
The answer depends on how often you roll it! For one roll it is 1/6 but the probability increases to a near certainty as you increase the number of rolls.