Math and Arithmetic

Statistics

Probability

Each toss has a 1/2 probability of getting heads. Each toss is an independent event. So three heads in a row (heads AND heads AND heads) would have a probability of:1/2 * 1/2 * 1/2 = (1/2)^3 = 1/(2^3) = 1/8 = 12.5%

In a large enough number of tosses, it is a certainty (probability = 1). In only the first three tosses, it is (0.5)3 = 0.125

The probability of tossing a die and getting three 6's in a row is (1/6)3, or about 0.004630.

Ideally, the probability of getting any specific combination of length n is 0.5n = 1/2n. For n = 3, this is 0.125 = 1/8.

The opposite of getting at most two heads is getting three heads. The probability of getting three heads is (1/2)^2, which is 1/8. The probability of getting at most two heads is then 1 - 1/8 which is 7/8.

The probability of something NOT happening is the complement of the probability of something happening. Since the probability that you DO have 3 heads is 1/8 (that is, 1/2 cubed), the complement is 1 - 1/8 = 7/8.

well it depends on what you are tossing, if its a coin then no. it can be heads too. it would have to be a great coincidence for it to be all tails, but thats why the word probability comes in meaning that there is more than one outcome

There are 8 permutations of three coins. Of these, 3 of them have two heads, so the probability of tossing two heads on three coins is 3 in 8, or 0.375. However, you said, "at least", so that includes the case of three heads, so the probability of throwing at least two heads is 4 in 8, or 0.5. T T T T T H T H T T H H * H T T H T H * H H T * H H H *

The probability of getting a head first time is one out of two, or a half. The probability of getting a head the next time is still one out of two, so the combined probability is one quarter. Similarly, one eighth is the probability of getting three in a row; but the pattern does not end there, the probability of getting a tails the next time is STILL one in two, so that is a one in sixteen chance of that run, the probability of the entire sequence is therefore one in thirty-two.

First event is to roll a 3 or 6 on a die, which gives you a probability of 2 out of 6. Second event is tossing a heads on a coin, so a probability of 1 out of 2. Since both chances are not related, you can multiply both chances: 2/6 times 1/2 = 1/6 = 0,166666...

For 3 coin flips: 87% chance of getting heads at least once 25% chance of getting heads twice 13% chance of getting heads all three times

The probability of getting an even sum on two dice is 18 in 36 or 1 in 2 or 0.5. The probability of doing that three times in a row is 0.53 or 0.125.

the probability of getting heads-heads-heads if you toss a coin three times is 1 out of 9.

4/16 or 1.44/16 or 1.44/16 or 1.44/16 or 1.4

Each time you toss the die the probability of rolling an even number is 3 out of 6 or 1/2. So, the probability of tossing three consecutive even numbers is (1/2)3 = 1/8 = 0.125, which is one chance in eight.

It is 93/256 = 0.363 approx.

The probability of any 1 result of tossing a coin 5 times, for example HHTHH or TTTTH, is 1/2^5 = 1/32. To find out how many of these results involve getting 3 heads, say HHHTT or HHTHT, we use the calculation 5!/(3!*2!), which = 10. Finally we multiply these 2 results to get 10/32 = 5/16.

Since a coin has two sides and it was tossed 5 times, there are 32 possible combinations of results. The probability of getting heads three times in 5 tries is 10/32. This is 5/16.

The probability is 0.09766%.Each toss has a ½ chance to be heads. To combine probabilities use multiply them. So the probability to get two heads out of two tosses is ½ * ½, and three heads out of three tosses is ½ * ½ * ½. So the exact answer is 0.5^10

Each coin toss is a Bernoulli trial with a probability of success of .5. The probability of tossing heads exactly 3 times out of five is3 ~ Bin(5, 1/2), which equals(5!/(3!(5-3)!))(0.5^3)(1-0.5)^(5-3), which is 0.3125.

The probability of getting all heads if you flip a coin three times is: P(HHH) = 1/2 ∙ 1/2 ∙ 1/2 = 1/8. The probability of getting all tails if you flip a coin three times is: P(TTT) = 1/2 ∙ 1/2 ∙ 1/2 = 1/8. The probability of getting all heads or all tails if you flip a coin three times is: P(HHH or TTT) = P(HHH) + P(TTT) = 2/8 = 1/4.

In three tosses, the probability is 3/8.

When we toss a coin getting head or tail have equal probability of 50% - that is, out of the two possible outcomes getting the specified one becomes 1/2 probability. When we toss three coins, the probability of getting all the coins showing tails is given by (1/2) * (1/2) * (1/2) equal to 1/8 or 12.5 % chance. Alikban

Pr(At least one head in three tosses) = 1 - Pr(No heads in three tosses) = 1 - Pr(Three tails in three tosses) = 1 - (1/2)*(1/2)*(1/2) = 1 - 1/8 = 7/8 or 0.875 or 87.5%

three heads two head, one tails one heads, two tails three tails

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