Math and Arithmetic

Statistics

Probability

Top Answer

(1/2)*(1/2)*(1/2)*(1/2)*(1/2)*(1/2) = 1/26 = 1/64

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0Five coin flips. Any outcome on a six-sided die has a probability of 1 in 6. If I assume that the order of the outcome does not matter, the same probability can be achieved with five flips of the coin. The possible outcomes of five flips of a coin are as follows: 5 Heads 5 Tails 4 Heads and 1 Tails 4 Tails and 1 Heads 3 Heads and 2 Tails 3 Tails and 2 Heads For six possible outcomes.

The probability of the coin flip being heads or tails is 100%.

The probability is 0%. The result will be heads or it will be tails but it cannot be heads and tails.

There are 8 possible outcomes when a coin is tossed 3 times. Here they are:1. Heads, Heads, Tails.2. Heads, Tails, Heads.3. Tails, Heads, Heads.4. Heads, Heads, Heads.5. Tails, Tails, Heads.6. Tails, Heads, Tails.7. Heads, Tails, Tails.8. Tails, Tails, Tails.There is only one outcome that is heads, heads, heads, so the probability of three heads coming up in three coin tosses is 1 in 8 or 0.125 for that probability.

This is a probability question. Probabilities are calculated with this simple equation: Chances of Success / [Chances of Success + Chances of Failure (or Total Chances)] If I flip a coin, there is one chance that it will land on heads and one chance it will land on tails. If success = landing on heads, then: Chances of Success = 1 Chances of Failure = 1 Total Chances = 2 Thus the probability that a coin will land on heads on one flip is 1/2 = .5 = 50 percent. (Note that probability can never be higher than 100 percent. If you get greater than 100 you did the problem incorrectly) Your question is unclear whether you mean the probability that a coin will land on head on any of 8 flips or all of 8 flips. To calculate either you could write out all the possible outcomes of the flips (for example: heads-heads-tails-tails-heads-tails-heads-heads) but that would take forvever. Luckily, because the outcome of one coin flip does not affect the next flip you can calculate the total probability my multiplying the probabilities of each individual outcome. For example: Probability That All 8 Flips Are Heads = Prob. Flip 1 is Heads * Prob. Flip 2 is Heads * Prob. Flip 3 is Heads...and so on Since we know that the probability of getting heads on any one flips is .5: Probability That All 8 Flips Are Heads = .5 * .5 * .5 * .5 * .5 * .5 * .5 * .5 (or .58) Probability That All 8 Flips Are Heads = .00391 or .391 percent. The probability that you will flip a heads on any of flips is similar, but instead of thinking about what is the possiblity of success, it is easier to approach it in another way. The is only one case where you will not a heads on any coin toss. That is if every outcome was tails. The probability of that occurring is the same as the probability of getting a heads on every toss because the probability of getting a heads or tails on any one toss is 50 percent. (If this does not make sense redo the problem above with tails instead of heads and see if your answer changes.) However this is the probability of FAILURE not success. This is where another probability formula comes into play: Probability of Success + Probability of Failure = 1 We know the probability of failure in this case is .00391 so: Probability of Success + .00391 = 1 Probability of Success = .9961 or 99.61 percent. Therefore, the probability of flipping a heads at least once during 8 coin flips is 99.61 percent. The probability of flipping a heads every time during 8 coin flips is .391 percent.

Since it is a certainty that a coin must land on either heads or tails, the probability must be 1.

Your question is slightly vague, so I will pose a more defined question: What is the probability of 3 coin tosses resulting in heads exactly twice? This is a pretty easy question to answer. The three possible (winning) outcomes are: 1. Heads, Heads, Tails. 2. Heads, Tails, Heads. 3. Tails, Heads, Heads. If we look at the possible combination of other (losing) outcomes, we can easily determine the probability: 4. Heads, Heads, Heads. 5. Tails, Tails, Heads. 6. Tails, Heads, Tails. 7. Heads, Tails, Tails. 8. Tails, Tails, Tails. This means that to throw heads twice in 3 flips, we have a 3 in 8 chance. This is because there are 3 winning possibilities out of a total of 8 winning and losing possibilities.

Each time you flip a coin, the probability of getting either heads or tails is 50%.

The probability of a fair coin landing on heads or tails is even, i.e. 50/50.

If you mean what is the probability of getting a heads/tails, it is a 1 in 2 chance (50/50 chance). You are just as likely to get a heads as you are to get a tails.

It is 100%. The coin will result in heads or tails since there are no other possible outcomes.

The probability of obtaining 7 heads in eight flips of a coin is:P(7H) = 8(1/2)8 = 0.03125 = 3.1%

There are two sides to the coin, so the probability of getting heads or tails on one flip of the coin is 1/2 or 50%.

Coins do not have numbers, there is only the probability of heads or tails.

The requirement that one coin is a head is superfluous and does not matter. The simplified question is "what is the probability of obtaining exactly six heads in seven flips of a coin?"... There are 128 permutations (27) of seven coins, or seven flips of one coin. Of these, there are seven permutations where there are exactly six heads, i.e. where there is only one tail. The probability, then, of tossing six heads in seven coin tosses is 7 in 128, or 0.0546875.

Because you are thinking permutations rather than combinations. There are four permutations of two coins, but there are only three combinations, because it does not matter which coin is heads and which coin is tails. As a result, the combination of heads and tails has a 0.5 probability, while two heads or two tails each have a 0.25 probability.

If you know that two of the four are already heads, then all you need to find isthe probability of exactly one heads in the last two flips.Number of possible outcomes of one flip of one coin = 2Number of possible outcomes in two flips = 4Number of the four outcomes that include a single heads = 2.Probability of a single heads in the last two flips = 2/4 = 50%.

The experimental probability of a coin landing on heads is 7/ 12. if the coin landed on tails 30 timefind the number of tosses?

The probability of getting all heads or all tails in 5 flips of a coin is 1 in 16.The probability of getting a head or a tail on the first flip is 1 in 1. The probability of each of the following coins matching the first coin is 1 in 2. Simply multiply the five probabilities (1 in 1) (1 in 2) (1 in 2) (1 in 2) (1 in 2) and you get 1 in 16.It is true that the probability of getting all heads is 1 in 32, and the probability of getting all tails is also 1 in 32. Since the question asked the probability of both cases (all heads or all tails), the answer is 1 in 16.

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