Assuming of course that we are talking about cubic dice.
combinations that make 9:
6&3, 5&4, 4&5, 3&6. There are 4 combinations that make 9.
There are 36 possible combination of two dice.
So 4/36 is 1/9
It is 5/18.
It is 10/36 = 5/18
The probability of rolling 7 once with two dice is 1 in 6, o 0.1667. The probability, then, of doing that twice in a row is 1 in 36, or 0.02778.
The probability of rolling two prime numbers on a standard pair of dice is 1 in 4, or 0.25. Take the probability of rolling a prime on one die, 3 in 6, or 1 in 2, or 0.5, and square it.
When rolling one die, the probability of getting a 4 is 1 in 6, or 0.1667. If two dice are rolled, you get two unrelated chances of rolling at least one 4, so the probability is 2 in 6, or 0.3333.
11/12
It is 5/18.
It is 1/12.
It is 10/36 = 5/18
The probability is 1/36.
The best way to do this is to note that this is 1 minus the probability of obtaining a sum less than 6. The probability of obtaining a 2 is 1/36 (both dice get 1) The probability of obtaining a 3 is 1/18 (one dice gets 1, the other gets 2, or the other way around) The probability of obtaining a 4 is 1/12 (both dice get 2, or one dice gets 1 and the other 3, or the other way around) The probability of obtaining a 5 is 1/9 (one dice gets 2 and the other 3, or the other way around, or one dice gets 1 and the other 4, or the other way around) Adding these probabilities up gives 5/18. 1 minus this is 13/18 Thus the probability of obtaining a sum of at least 6 when rolling a pair of dice is 13/18.
It is 0.69444... recurring.
The probability of rolling two fives on a pair of dice is 1 in 36, or about 0.02778.
5 over 11
The probability of rolling 7 once with two dice is 1 in 6, o 0.1667. The probability, then, of doing that twice in a row is 1 in 36, or 0.02778.
It is 6/36 = 1/6.
The probability of rolling a sum of 8 on one roll of a pair of dice is 5/36.The probability of not rolling a sum of 8 on one roll of a pair of dice is 31/36.The probability of rolling a sum of 8 twice on two rolls of a pair of dice is(5/36)(5/36) = (5/36)2 .The probability of rolling first a sum of 8 and then rolling a sum that is not 8 on thesecond roll is (5/36)(31/36).The probability of rolling a sum that is not 8 on the first roll and rolling a sum of 8in the second roll is (31/36)(5/36).So The probability of rolling a sum of 8 at least one of two rolls of a pair of dice is(5/36)2 + (5/36)(31/38) + (31/36)(5/36) = 0.258487654... ≈ 25.8%.