A sum that is a multiple of 3: 3, 6, 9 and 12.
(1,2), (2,1), (1,5), (5,1), (3,3), (4,2), (2,4), (2,7), (7,2), (3,6), (6,3), (4,5), (5,4), and (6,6) ignore them because they are doubles.
Doubles: (1,1), (2,2), (3,3), (4,4), (5,5) and (6,6).
18 favorable outcomes/36 total outcomes = 1/2 = 0.5
2/9
I'm going to assume you mean rolling the same number twice in a row in 25 rolls. The first won't cause a double, so you just need to consider the odds of rolling the same number as the last for the last 24 rolls. The easier approach is to realize that the probability of rolling at least one double is 1 minus the probability of rolling no doubles. One roll has this probability of not rolling the same as the last: P(different number from last) = 5/6 Since they are independent events: P(no doubles in 25 rolls) = (5/6)24 Now the final probability, of at least one double, is 1 - (5/6)24
The probability of rolling a 2 is 1 in 6. The probability of rolling an even number is 3 in 6. The probability of doing both, on two rolls, is 3 in 36, or 1 in 12.
1 in 6.
The probability of rolling doubles on a pair of dice is 1 in 6, or about 0.1667.
There could be many questions: What is the probability of rolling an even number. What is the probability of rolling an odd number. What is the probability of rolling a number less than 4. What is the probability of rolling a number more than 3. What is the probability of rolling 1,4, or 6. Basically it could be any question about the probability of rolling half of the faces.
2/9
It is 1/6.
The probability is 11/36.
when rolling a number cube when rolling a number cube what is the probability of rolling an even number or a divisor of 10? rolling an even number or a divisor of 10?
I'm going to assume you mean rolling the same number twice in a row in 25 rolls. The first won't cause a double, so you just need to consider the odds of rolling the same number as the last for the last 24 rolls. The easier approach is to realize that the probability of rolling at least one double is 1 minus the probability of rolling no doubles. One roll has this probability of not rolling the same as the last: P(different number from last) = 5/6 Since they are independent events: P(no doubles in 25 rolls) = (5/6)24 Now the final probability, of at least one double, is 1 - (5/6)24
The probability of rolling a 2 is 1 in 6. The probability of rolling an even number is 3 in 6. The probability of doing both, on two rolls, is 3 in 36, or 1 in 12.
The probability would be 5/6 for rolling a number other than a 3.
The probability of rolling a number greater than 6 on a die is 0.
The probability of rolling an odd number on a standard die is 3 in 6, or 1 in 2, or 0.5.
1 in 6.
The probability is 57/216 = 19/108