Well there is 36 different possibilities with rolling 2 6 sided dice.
The probability of rolling the sum of 10 with 2 die is 4/36 or 1/8 chance.
It is 0.0833... recurring.
There is one way to roll a sum of 12. There are 36 different outcomes from rolling a pair of dice. Therefore, the probability is 1/36 ~= 0.0278 = 2.78%
It is 10/36 = 5/18 in a single throw of a pair of dice.
If the question is: What are the odds of rolling a die with a 6 when rolling twodice ? . Answer: There are 36 outcomes when rolling a pair of dice, 10 of themhave a die with a single 6 and 1 of them has two 6. So the probability of rollingone die with a 6 when rolling a pair of dice is P =10/36 =0.2777... . The oddswould be (10 to 26) 5 to 13.If the question is: What are the odds of rolling a sum of 6 when rolling two dice ?Answer: there are 5 outcomes out of the 36 that give the sum of 6. They are;(1,5), (5,1), (2,4), (4,2), and (3,3). So the probability for this event is P =5/36 =0.13888... . The odds would be 5 to 31.
With 3 fair dice, pipped 1 through 6, there are 10 permutations that add up to 6. They are 114, 123, 132, 142, 213, 222, 231, 312, 321, and 411. The total number of permutations of the three dice is 63 or 216. The probability, then, of rolling a sum of 6 on 3 dice is 10 in 216, or 5 in 108, or about 0.0463.
Assuming that the random variable is the sum of the two numbers rolled, the answer is 3/36 or 1/12.
There are 36 permutations of two dice. Of these, 10 sum to less than six; 1+1, 1+2, 1+3, 1+4, 2+1, 2+2, 2+3, 3+1, 3+2, and 4+1. The probability, then, of rolling a sum less than six is 10 in 36, or 5 in 18, or about 0.2778.
The probability of rolling 6 ones with 10 dice is: 10C6 (1/6)6 (5/6)4 = 2.170635034...x 10-3 ≈ 0.22%
3 times (out of 36) is the probablility Possible Outcome 1 - Dice 1: 4, Dice 2: 6 Possible Outcome 2 - Dice 1: 5, Dice 2: 5 Possible Outcome 3 - Dice 1: 6, Dice 2: 4
The probability is 21/36 = 7/12
The probability is 8/36 or 2/9
If only one of the 10 sides is numbered 4, the answer is 1/10.
In one throw, it is 3/36 or 1/12
With two tetrahedral dice labelled 1-4 the probability is zero as the maximum score possible is 8.With two cubical dice labelled 1-6, the probability is 6/36 = 1/6Other d&d dice (d8, d10, d12, d20) are left as an exercise for the reader.
There are 36 different combinations when rolling two dice, of these, there is a 10/36 = 5/18 (27.78%) chance of rolling combined total of 9 or more, or a 6/36 = 1/6 (16.67%) chance of rolling a combined total of 10 or more
If there is a different number on each face of the die and no numbers a repeated it is a 1 in 10 chance.
The probability is (0.1) times (the number of faces with '4' marked on them).
There is an approximately 8% chance of that, or 1 out of 12.
The probability of rolling a multiple of five on a standard die is 1 in 6, or about 0.1667.The probability of rolling a 10, 15, or higher is zero, because the question implied only one die.
There are 216 permutations of three standard dice. Of these, there are exactly 10 that sum to 15, namely 3-3-6, 4-5-6, 4-6-5, 5-4-6, 5-5-5, 5-6-4, 6-3-6, 6-4-5, 6-5-4, and 6-6-3. The probability, then, of rolling a sum of 15 with three standard dice is 10 in 216, or 5 in 108, or about 0.04630.
The combinations that produce a 10 are (4,6),(5,5) and (6,4), and there are 36 combinations (6 x 6) possible, so 3/36 = 1/12. So one chance in 12. The probability is 0.0833.
There are 36 different outcomes when rolling two dice. 4 combinations make 9. 3 make 10, 2 make 11 and 1 makes 12. 4+3+2+1 = 10 10 out of 36 = 10/36 = 0.277777 = 27.8 %
Each cube can land in 6 different ways.Two cubes can land in (6 x 6) = 36 different ways.There are 3 different ways of rolling a ten:4 - 65 - 56 - 4The probability of rolling a ten is (3 / 36) = 1/12 = 8 and 1/3 percent
If the dice is 6 sided, the chances of rolling each number is about 17% (100/6) If the dice is 4 sided, the chances of rolling each number is 25% (100/4) Similarly, 8 sided = 12.5% 10 sided = 10% 12 sided ≈ 8% 20 sided = 5%