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Answered 2012-11-26 23:14:27

3 coins can land in 8 different ways. Only one of these ways is all tails.

So the probability of rolling at least one heads is 7/8 = 87.5% .

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Probability of no heads = (0.5)^5 = 0.03125Probability of at least one head = 1 - probability of no heads = 1 - 0.03125 = 0.96875


By tossing two coins the possible outcomes are:H & HH & TT & HT & TThus the probability of getting exactly 1 head is 2 out 4 or 50%. If the question was what is the probability of getting at least 1 head then the probability is 3 out of 4 or 75%


Probability not at least 1 head showing is when all 5 coins are tails: (1/2)5=1/32 Therefore probability at least 1 head is showing is 1-1/32=31/32


This is easiest to solve by working out the probability that no heads show and subtracting this from 1 to give the probability that at least one head shows: Assuming unbiased coins which won't land and stay on their edge, the probability of head = probability of tail = ½ → probability no heads = probability 5 tails = ½^5 = 1/32 → probability of at least one head = 1 - 1/32 = 31/32 = 0.96875 = 96.875 % = 96 7/8 %



No matter how many coins are thrown, the possibility of having AT LEAST ONE 'head' is 50%. This changes if you specify the number of 'heads' that must be shown.


Assuming a two-sided coin, and that you make the the toss, the probability of tossing a head or a tail is 100%. The probability of tossing a head is 50%. The probability of tossing a tail is 50%.


The probability of tossing a coin and getting heads is 0.5


There are 2 coins, 1 and 2. Each has two possibilities, H or T. The possibilities are: 1H, 2H 1H, 2T 1T, 2H 1T, 2T Each possibility has an equal chance of happening. The chance of tossing at least one head is 3/4.


you toss 3 coins what is the probability that you get exactly 2 heads given that you get at least one head?


The chance for each toss is 1/2. The chance of all three flips being tails is 1/2 * 1/2 * 1/2 = 1/8. So the probability of at least one head is 7/8.


The probability that you will toss five heads in six coin tosses given that at least one is a head is the same as the probability of tossing four heads in five coin tosses1. There are 32 permutations of five coins. Five of them have four heads2. This is a probability of 5 in 32, or 0.15625. ----------------------------------------------------------------------------------- 1Simplify the problem. It asked about five heads but said that at least one was a head. That is redundant, and can be ignored. 2This problem was solved by simple inspection. If there are four heads in five coins, this means that there is one tail in five coins. That fact simplifies the calculation to five permutations exactly.


Tossing two coins doesn't have a probability, but the events or outcomes of tossing two coins is easy to calculate. Calling the outcomes head (H)or tails (T), the set of outcomes is: HH, HT, TH and TT as follows: 2 heads = (1/2) * (1/2) = 1/4 1 head and 1 tail, can be heads on first coin tails on second, or just the opposite, there's two possible events: (1/2)*(1/2) + (1/2)*(1/2) = 1/2 2 tails = same probability as two heads = 1/4


the probability of tossing a coin and it landing on head is a 1 in 2 chance the probability of rolling a 5 on a dice is a 1 in 6 chance


When we toss a coin getting head or tail have equal probability of 50% - that is, out of the two possible outcomes getting the specified one becomes 1/2 probability. When we toss three coins, the probability of getting all the coins showing tails is given by (1/2) * (1/2) * (1/2) equal to 1/8 or 12.5 % chance. Alikban


Pr(At least one head in three tosses) = 1 - Pr(No heads in three tosses) = 1 - Pr(Three tails in three tosses) = 1 - (1/2)*(1/2)*(1/2) = 1 - 1/8 = 7/8 or 0.875 or 87.5%


The probability of rolling a number less than 5; which is a 4, 3, 2, or 1 is 4/6 or 2/3. The probability of tossing a head is 1/2. So, the probability of a roll less than 5 and a head is 2/3*1/2 or 1/3 or 0.333. 4/12


on one coin, the probability of getting a head is 0.5, if there is no bias



The probability of a head is 1/2. The probability of an odd number is 1/2. 1/2 x 1/2 = 1/4 or 0.25



If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8If it is a fair coin, the probability of getting at least one Head from 3 flips is 7/8



In the experiment of tossing a fair coin 3 times, the sample space is made of thefollowing 8 equiprobable events: S = {HHH, THH, HTH, HHT, TTH, THT, HTT, TTT}.The events that at least have one head are 7. So the probability of getting at leastone head on three tosses is: P(at least one H) = 7/8 = 0.875 = 87.5%


There are 8 permutations of three coins. Of those, three of them have only one head, so the probability of throwing only one head is 3 in 8, or 0.375. However, you said, "at most", and that includes the permutation that does not include any heads at all, so the probability of throwing at most one head in three coins is 4 in 8, or 0.5. T T T * T T H * T H T * T H H H T T * H T H H H T H H H