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What is the probability of tossing two 6-sided die three times and getting an even number all three times?

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The probability of getting an even sum on two dice is 18 in 36 or 1 in 2 or 0.5. The probability of doing that three times in a row is 0.53 or 0.125.

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1/2 * 1/2 = 1/4 1/2= probability of landing an even number 1/2 = probability of landing a heads

Zero. Since coins land on Heads or Tails and not numbers.

The probability of an event is the number of favourable outcomes divided by the total number of possible outcomes. What is the total number of possible outcomes of tossing a number cube? 6 How many outcomes are favourable to the event of getting a five? 1 So the prob is 1/6 or 0.16667

The probability of tossing an odd number (assumed on a die) is 3 in 6 or 1 in 2. The probability of tossing a tail (assumed on a coin) is 1 in 2. Since these are unrelated events, and the question said "and", simply multiply the probabilities to get 1 in 4.

First probability of getting 2 is one in six: 1/6probability of getting no greater than 4 is two chances in six (must be a 5 or 6): 2/6=1/3so probability = 1/6*1/3= 1/18.

In a large enough number of tosses, it is a certainty (probability = 1). In only the first three tosses, it is (0.5)3 = 0.125

Firstly, the probability when tossing a coin and getting a head or tail is 1/2, then rolling a die, there are 6 sides so the chance of rolling any number is 1/6, there are 2 chances of rolling greater than 4 ie 5 and 6, so the probability of rolling a 5 or 6 in 1/3, as these are independent events you multiply the probability getting a heads of tails, (1/2) by the probability of rolling a five or six, (1/3) which gives you 1/6 or 0.1666 recurring.

The probability of tossing a 1 or 2 on a six sided die is 2 in 6, or 1 in 3.

There are 36 possibilities when rolling two six sided die. 15 of them result in a prime number (2,3,5,7,11) So the probability is 15 in 36 or a 5 in 12 chance.

there are three distinct outcomes1,3or5. But there is no probability which will come.

Each time you toss the die the probability of rolling an even number is 3 out of 6 or 1/2. So, the probability of tossing three consecutive even numbers is (1/2)3 = 1/8 = 0.125, which is one chance in eight.

The probability of the first one is 1/6 .The probability of the second one is 1/6 .The probability of the third one is 1/6 .The probability of the fourth one is 1/6 .The probability of all four is (1/6)4 = 0.0007716 (rounded) = 0.077 %

A die has six sides, so the probability of rolling an even number is 1 in 2, or 50-50. A coin has two sides, so the probability of flipping the coin and getting heads is 1 in 2, or 50-50. The probability that both will happen together is the one in two OF one in two, or one in FOUR chance that both will happen. So, the probability is 25%.

The probability of a head is 1/2. The probability of an odd number is 1/2. 1/2 x 1/2 = 1/4 or 0.25

The probability of rolling a number less than 5; which is a 4, 3, 2, or 1 is 4/6 or 2/3. The probability of tossing a head is 1/2. So, the probability of a roll less than 5 and a head is 2/3*1/2 or 1/3 or 0.333. 4/12

The result of tossing the coin would not affect which number was selected. So we say that these two events are independent. We can therefore assess the probability of each of them separately and then multiply the two probabilities together for a final result. Probability of getting tails: 1/2 (since there is one way of getting heads out of two possibilities) Probability of getting zero: 1/10 (since there is one way of getting zero out of ten possibilities) Overall probability: 1/2 x 1/20 = 1/20

The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.

252/1024 or 0.246. One method of calculating it is this: The total number of outcomes possible by tossing a coin 10 times is 2 to the 10th, which is 1024. In addition, getting 5 heads in 10 tosses is like arranging 5 identical objects in 10 spaces (the remaining 5 spaces are by default Tails), which can be done in 10C5 ways, which is 252. So the probability of getting 5 heads is 252/1024.

The empirical probability can only be determined by carrying out the experiment a very large number of times. Otherwise it would be the theoretical probability.

Each face has probability 1/6, since it's one face out of the possible 6. So the probability of either of two faces is 2/6, or 1/3.

No. The number of outcomes is 24 which is 16, not 64. Furthermore, probability is a number that is associated with an outcome and is a number in the range [0, 1]. Neither 16 nor 64 are number in the relevant range.

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