3 % No, not correct.
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The probability that a single person would have a birthday in March is 1 out of 12 (because there are 12 months in the year). Hence the probability that one of 40 students would have a birthday in March is 40 x 1/12 = 10/3 = 33.33%; More accurately March has 31 days out of 365 days min the year so the probability of one person having a birthday in March is 31/365, and for 40 students it would be 4 x 31/365 = 124/365 = 0.3397(to 4 decimal places) = 34% to nearest 1%
None. The full name is the Probability Distribution Function (pdf).
For a normal deck of cards, the answer is none.
None of the digits can be 10, so the probability is 0.
23. The probability that at least two people in a room share a birthday can be expressed more simply, mathematically, as 1 minus the probability that nobody in the room shares a birthday.Imagine a fairly simple example of a room with only three people. The probability that any two share a birthday is :1 - [ 365/365 x 364/365 x 363/365]i.e. 1-P(none of them share a birthday)=1 - [ (365x364x363) / 3653 ]=0.8%Similarly,P(any two share a birthday in a room of 4 people)= 1 - [ 365x364x363x362 / 3654 ] = 1.6%If you keep following that logic eventually you getP(any two share a birthday in a room of 23 people)=1 - [(365x364x...x344x343) / 36523 ] = 51%
None, if you do not have the necessary qualifications.
This is none of our business. Even public personalities have some right to privacy.
None. If you have an exact relationship - whether it is linear, polynomial, logarithmic or whatever - probability has no role to play.
none none none
NOne that was the day the myans predicted no babies would be born they all die\
the probability of a house will be burglarized is = 5% which is = .05 the probability of a house will NOT be burglarized is = (1 - .05) the probability of a second house will NOT be burglarized is = (1-.05)*(1-.05)= (1-.05)^2 the probability of a third house will NOT be burglarized is= (1-.05)*(1-.05)(1-.05)= (1-.05)^3 so, the probability of NONE = (1-.05)^10 = .598736939 = .5987
No they do not, all my webkinz have had their birthday and none of them have expired.
The Probability of NOT reading newspaper a is .8 The Probability of NOT reading Newspaper b is .84 The probability of NOT reading Newspaper c is .86 Therefore, .8*.84*.86=0.57792=57.792%