It is (1/6)2 = 1/36
With fair regular dice, the answer is 4/36 = 1/9
Of the 36 possible combinations rolling two dice there are 2 combinations that add up to 11 so the odds are 18:1
With 3 fair dice, pipped 1 through 6, there are 10 permutations that add up to 6. They are 114, 123, 132, 142, 213, 222, 231, 312, 321, and 411. The total number of permutations of the three dice is 63 or 216. The probability, then, of rolling a sum of 6 on 3 dice is 10 in 216, or 5 in 108, or about 0.0463.
1:18. There are 36 potentials and only two can add to 3. Thus one in eighteen
On a fair die the probability is 1 (a certainty). The probability of it happening on a single roll is 0.5==========All answers below assume a single roll using unbiased 6 sided die/dice (as may boardgamers and RPG players are aware, there are 4, 8, 10, 12, and 20 sided dice easily available too)For 1 die, the probability is 3/6 = 1/2 (3 ways to roll higher than 3 and six possible rolls)For 2 dice it is 33/36 = 11/12 (36 possible combinations, of which 33 are more than 3)For 3 dice it is 215/216 (216 possible combinations with one - 1,1,1 - not being greater than 3)For 4 or more dice your probability is 100% since the lowest you can roll is all 1's which would add up to the number of dice - which will be greater than 3 if the number of dice is greater than 3.
With fair regular dice, the answer is 4/36 = 1/9
There are 36 permutations of rolling two dice. Three of them, (4,6), (5,5), and (6,4) add up to ten. Therefore, the probability of rolling ten on two dice is 3 in 36, or 1 in 12, or about 0.0833.
The probability of rolling a 7 with 2 dice is 6/36; probability of rolling an 11 is 2/36. Add the two together to find probability of rolling a 7 or 11 which is 8/36 or 2/9.
The answer depends on what numbers are on the faces of the dice.
Of the 36 possible combinations rolling two dice there are 2 combinations that add up to 11 so the odds are 18:1
With 3 fair dice, pipped 1 through 6, there are 10 permutations that add up to 6. They are 114, 123, 132, 142, 213, 222, 231, 312, 321, and 411. The total number of permutations of the three dice is 63 or 216. The probability, then, of rolling a sum of 6 on 3 dice is 10 in 216, or 5 in 108, or about 0.0463.
1:18. There are 36 potentials and only two can add to 3. Thus one in eighteen
The probability of rolling (2, 6) is (1/6)2=1/36 Add 1/36 for all the other ways to roll 8 - (3,5),(4,4),(5,3),(6,2) Total probability is 5/36
On a fair die the probability is 1 (a certainty). The probability of it happening on a single roll is 0.5==========All answers below assume a single roll using unbiased 6 sided die/dice (as may boardgamers and RPG players are aware, there are 4, 8, 10, 12, and 20 sided dice easily available too)For 1 die, the probability is 3/6 = 1/2 (3 ways to roll higher than 3 and six possible rolls)For 2 dice it is 33/36 = 11/12 (36 possible combinations, of which 33 are more than 3)For 3 dice it is 215/216 (216 possible combinations with one - 1,1,1 - not being greater than 3)For 4 or more dice your probability is 100% since the lowest you can roll is all 1's which would add up to the number of dice - which will be greater than 3 if the number of dice is greater than 3.
6
Assuming you meant a standard pair of dice, only 1 and 1 add to 2, since there are no negatives, and numbers only stretch up to 6, and due to that, there is no 0. Therefore, 1/36 is the probability (probability of rolling a 1, 1/6, probability of rolling a 1, 1/6, 1/6(1/6) = 1/36).
I think of it this way. Take it as two unique 6-sided dice, then you have 36 possible outcomes (6 times 6). Two of these outcomes will add to equal 3 (2 & 1, and 1 & 2), so there are 34 [36-2] outcomes which don't sum to 3. The probability is 34/36 or about 94.44 percent chance. If you're asking what the probability you don't roll AT LEAST three is, the only roll on two normal dice less than three is two, and there's only one way to roll it: 1,1. So the probability of not getting AT LEAST three on two fair dice is 1/36.