Lol isn't it just 2m-5 (or 2(m-5) depending on how you read it)
1
10-m
5m + 13
2 m south
When multiplied together, an odd number and an even number will always produce an odd number. Two consecutive numbers consist of one odd number and one even number, so their product is always an odd number. N-n-n-no! Any number multiplied by an even number yields an even product. Ever;y even number can be expressed as 2*M for some M. If we multiply 2*M by Y, the product is 2*M*Y = 2*(M*Y) which is even. So the right answer is: They don't! The product of two consecutive numbers is always even. Regards, Bill Drissel
If we are to find the product of 5 and m and n/2 (which is half of n), we have: 5 times m times n/2 = 5 x m x n/2 = 5mn/2
5 decreased by 4 times m=1 Step-by-step: 1)5-4m 2)1m (When a letter is alone, it means it is 1) 3)1x1 (When a number is next to a number, it means multiply) Answer is 1
5(m-2) - m(m-2)
(m + 2) - x
5(m-2) - m(m-2)
5(m-2) - m(m-2)
You need to find factors whose sum is 10 and product is 25. Here, it is a square, and the number is 5. m^2 +10m +25 = (m+5)(m+5)
m+5/2=m/2+5/2
(5-2x+m)2
1
10-m
5m + 13