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Only one product is 2-chloro butane.

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14y ago
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Q: What is the product of the chemical reaction of 2-butene and HCI?
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Related questions

If the reactants of a reaction are HCI and NaOH what could be a product?

NaCl


What is the chemical reaction for Ca plus Hci?

Ca + 2 HCl = CaCl2 + H2


What salt is formed when NaOH is neutralised by HCI?

The product of this reaction is salt:NaOH + HCl = NaCl + H2O


What happened when chlorine and hydrochloric acid combine to each other?

when chlorine mix to Hydrochloric acid (HCI) it will produce of product of Hydrogen gas and Zinc Chloride. During Chemical Reaction the particles of two chemical subtances will collide to each other and it will produce heat.


If the reactants of a reaction are HCI and NaOH what is the product?

Depending on the reaction, may be reactant or product.


What kind of chemical reaction is shown mg 2 hci---mgci2 h2?

Correctly represented, it's Mg + 2HCl --> MgCl2 + H2, and it's a single replacement reaction.


What product is formed in the reaction HCI NaOH?

NaOH + HCl --> NaCl + H2OWith the reaction of a strong base and a strong acid, a neutralization reaction, one sees a salt, sodium chloride here, and water.


What compound is used up in the reaction HCI NaOH?

First, its HCl, with a lowercase L, not HCI. The reaction is HCl + NaOH --> H2O + NaCl


The only reactants in a reaction were Zn and HCI. What does the law of conservation of matter say about the products?

The product will contain only Zn, H, and CI. -Apex


How do you tell if a reaction is blalanced?

if there is the same number of atoms on both sides e.g Mg + HcI-------------> Mg + HcI^2 (HcI squared) this is an unbalanced reaction because there is more chlorine on the right side than the left side. so when you balance the equation it will look like this: MG + HcI^2------------------>Mg +HcI^2


What type of reaction is NaOH plus HCI-------------- H2O NaCI?

An acid-base reaction


What is hci mean?

If you think yo HCl (not hci) this is the chemical formula of the hydrochloric acid.