Impossible to say without more detail. Oxidation includes burning to give CO2 and H2O
3-methylbutanoic acid
The oxidation state is +3.
+3 is the oxidation no of iron(III)
K = +1 oxidation state Cl = +3 oxidation state O = -2 oxidation state
+3 oxidation state
Assuming there is water present, I would expect the product to be a (roughly equal) mixture of 2-octanol and 3-octanol.
3-methylbutanoic acid
3-methyl-2-butanone
The oxidation state is +3.
+3 oxidation state
The oxidation number of Al is +3.
Regarding the oxidation states of the atoms in the tetrathionate ion: The tetrathionate polyatomic ion is made of four sulfur atoms, each with an oxidation number of +1, and six oxygen atoms each with an oxidation number of -1. Note, this is one of the rare exceptions to the 'rule' that oxygen normally has a minus two oxidation number. Other -1 oxygen compounds are the peroxides. An interesting half reaction is the oxidation of two thiosulfate ions to tetrathionate, in which sulfur has an oxidation number of +2 in the reactant and +1 in the product. Oxygen has an oxidation number of -2 in the reactant, and -1 in the product. 2S2O3-2 ----> S4O6-2 + 2 e-
Oxidation number of N is +3. Oxidation number of H is -1.
The +3 oxidation state is stable-
Which of the alkyl chlorides undergoes dehydrohalogenation in the presence of a strong base to give pent-2-ene as the only alkene product - the choices are: A 2-chloropentane B 1-chloro-2-methylbutane C 1-chloropentane D 3-chloropentane The answer is: 3-chloropentane
the oxidation number is +3.
oxidation state of Fe in FeCl3 is +3. Cl has oxidation number -1 in this case Fe share 3 electrons with Cl so its oxidation state is +3.