First of all place the numbers in rank order. Hence
46,57,68,72,72,93.
RANGE; is the difference between the highest and lowest numbers, which is 93-46 = 47
MEDIAN: is the absolute mid-point. Since there is no absolute mid-point, we take the two middle numbers , add them and divide by '2'. Hence. ( 68+72)/2 = 70
MODE: is the term that occurs most frequently. In this case '72'. as there are two of them , but only one each of the other terms.
MEAN; Add all the terms and divide by the number of terms.
(46+57+68+72+72+93) / 6 = 408/6 = 68
Range = 47
Median = 70
Mode = 72
Mean = 68
Mean = Sum of values/Number of values = (46+35+...+43)/7 = 266/7 = 38 Median = Value in middle ie 4th position of ordered values = 37 Mode = Each of the seven values (some would say none). Range = Maximum - Minimum = 53 - 23 = 30
There is no simple relationship between the three measures of central tendency. There may not be a mode or there may be several and if there is only one, it can have any value.
Mean: 40.17Median: 40Mode:noneRange: 1135, 37, 38, 42, 43, 46Mean is the average:(35 + 37 + 38 + 42 + 53 + 56)/6 = 241/6 = 40.17Median is the middle value in the list = 3rd & 4th values(38 +42)/2 = 80/2 =40Mode is thenumber that is repeated more often =noneRange is the largest value and the smallest value = 46 - 35 = 11
for the data set shown below find the interwar range IQR. 300,280,245,290,268,288,270,292,279,282
Steps:1.) Arrange the data either ascending or descending order of their values.2.) Determine the total number of observations, say n.3.) If the set of number is odd then the middle number will be the median. And if the set of number is even then mean of middle two numbers will be the median.a.) After that we'll be starting to discuss and give examples on how to find the median of ungrouped data.Example1:1.) Find the median of 12, 15, 10, 18, 8.2.) Arrange the data either ascending or descending order of their values.8, 10, 12, 15, 18(ascending)18, 15, 12, 10, 8(descending)3.) If the set of numbers is an odd integer, find the middle number in the set of numbers.From the above middle number 12 then 12 is the median.Example2:1.) Find the median of 23, 46, 18, 32, 65, 20.2.) Arrange the data either ascending or descending order of their values.18, 20, 23, 32, 46, 65(ascending)65, 46, 32, 23, 20, 18(descending)3.) If the set of numbers is an even integer, find the two middle numbers in the set of numbers.From the above we can say that there are two middle numbers23 and 32. So,Md = 23+32/2 = 27.5By: HuebosFb: Jupete02@yahoo.comTwitter: @kimjupetehuebos
A single number, such has, 7152484654452062 can have only one mean, median, mode. And the range is 0.
The mean is 53.The median is 53.5The range is 13.
Mean: 50.5 Median: 46 Mode: 33, 59, 86, 24
Mean = Sum of values/Number of values = (46+35+...+43)/7 = 266/7 = 38 Median = Value in middle ie 4th position of ordered values = 37 Mode = Each of the seven values (some would say none). Range = Maximum - Minimum = 53 - 23 = 30
3, 3, 3, 9, 9, 11, 12, 14, 15, 15, 23 Median is 11 Mode is 3 Range is 20
This is a set of data. What do you want calculating?? You do not say. From it you can measure , MODE , MEDIAN, MEAN & RANGE.
45, 46, 47, 48, 50, 50, 53, 54, 55
There is no simple relationship between the three measures of central tendency. There may not be a mode or there may be several and if there is only one, it can have any value.
Median 30 pounds. Range = 52 - 6 = 46 pounds.
23, 24, 26, 29, 30, 32, 33, 34, 35, 46, 37, 39, 40, 42, 45
The mean is the sum of all the numbers divided by the number of numbers which is 69 6/7 = 69.857142 repeating ≈ 69.86 The median is the middle number when the numbers are listed in order, and is 76. The mode is the number(s) with the highest frequency, and is 92. The range is the largest less the smallest which is 70.
56.5 (the mean of 49 and 64)