Copper is dissolved:2 FeCl3 + Cu = 2 FeCl2 + CuCl2
Double replacement reaction
what are the products of the reaction K2Cro4 and Fecl2
This reaction could not happen.
FeCl3 + 3NH4OH = Fe(OH)3 + 3NH4Cl
The reaction is:2 FeCl2 + Cl2 = 2 FeCl3
Zn is more reactive than is Cu, so it will replace the Cu. Thus, the reaction isZnSO4 + Cu ==> CuSO4 + Zn. This is an oxidation/reduction reaction.
Cl2 + 2Cu --> 2CuCl Oxidation reaction is Cu --> Cu+ + 1e Reduction reaction is Cl + 1e --> Cl- Redox reaction is Cu + Cl --> Cu+ + Cl-
exothermic reaction! (sudenly?)
Calcium(Ca), being a more reactive element, reacts with FeCl3 to produce CaCl2 and Iron(Fe).3 Ca + 2 FeCl3 ----> 3 CaCl2 + 2Fe
It is a Chemical Change
The reaction is: Fe(s) + CuSO4(aq)= FeSO4(aq) + Cu(s)
2 FeCl3 (aq) + 3 Mg (s) = 3 MgCl2 (aq) + 2 Fe (s) and/or 2 FeCl3 (aq) + Mg (s) = MgCl2 (aq) + 2 FeCl2 (aq).
Cu + 2Ag+ --> Cu2+ + 2Ag
The reaction is:Cu + 4 HNO3 = Cu(NO3)2 + 2 NO2 + 2 H2O
Apparently this is a trick question. Cu is too low in reactivity to actually have a reaction with the acid. So there is no reaction. Cu + HCl --> N/R
The chemical reaction is:2 Fe(s) + 3 Cl2(g) = 2 FeCl3
Yes, it can be. Example: Fe + CuSO4 ----------> FeSO4 + Cu Here Fe is oxidized to Fe2+ and Cu2+ is reduced to Cu.
The oxidation number of Cu as a reactant is zero (before a reaction).
Three examples of a single-displacement reaction are Cu + 2AgNO3 ---> 2Ag + Cu(NO3)2 Fe + Cu(NO3)2 ---> Fe(NO3)2 + Cu Ca + 2H2O ---> Ca(OH)2 + H2