When calculating kW, power factor is brought into the equation
Formula for single phase kVA = I x E/1000,
3 phase kVA = I x E x 1.73/1000
Formula for single phase KW = I x E x pf/1000,
3 phase kW = I x E x 1.73 x pf/1000
Alternative AnswerWhen an AC current flows through a purely resistive circuits, its temperature increases above the ambient temperature, and energy is lost to the surroundings through heat transfer. This energy transfer is irreversible. The rate at which this energy loss is taking place is called the true power of the circuit, and is expressed in watts (symbol: W).
When an AC current flows through a purely reactive (i.e. inductive or capacitive) circuit, during the first quarter-cycle, energy is stored in the magnetic or electric field, and returned to the circuit during the next quarter cycle. So, although energy transfer is taking place, there is no net loss of energy. The rate at which this energy transfer is taking place is called the reactive power of the circuit, and is expressed in reactive volt amperes(symbol: var).
However, most practical circuits are inductive-reactive circuits. So, when AC current flows through an inductive-reactive circuit, some energy is permanently lost while some energy is transferred from and back to the circuit. In other words, most circuits exhibit a combination of true power and reactive power. The vector sum of true power and reactive power is called apparent power, and is expressed in volt amperes (symbol: V.A).
To summarise:(Apparent Power)2 = (True Power)2 + (Reactive Power)2
From the above equation, in a purely resistive circuit, the apparent power will be equal to the true power. For resistive-reactive circuits, the apparent power will always be larger than the true power.
Read more: What_is_KW_and_KVA
1 HP = 746 watts = 0.746 KW Example of a 200 HP motor: KW = 200 x 0.746 = 149.2 KW
200 hp requires about 149kW
A 5 kW generator would turn it over but if the full 30 hp of mechanical power is needed, that would require about 30 kW of electric power from the generator.
if your talking about a generator its not the hp of the engine its the size, rpm, and gearing of the generator motor
1 watt is equal to 0.001 kW, or 0.00134048257373 hp so that means 0.001kw=0.00134048257373 hp so you times each side by 1,000 which would get you 1kw=1.34048257373hp so now times by your 45.6 so 45.6kw= 61.126005362088 hp
Kindly convert 5.44 BKW to kwAnswerIf, by 'Bkw', you mean 'brake kilowatts', then it's already in kilowatts! Incidentally, the symbol for kilowatt is 'kW', not 'kw' or 'Kw'.
The conversion factor is 0.746. So, hp x 0.746 = kW
One kW = 1.34 hp
99.2357 HP is 74 kw
2 kw is 2.68 hp (Kilowatts / Horsepower)
They both are the units of power, and they are commonly used to represent the power of vehicles. Relation goes like this: 1hp/bhp=745.70103354w 1kw=1.34102hp
metric HP is roughly 0.7354 kW 100 HP = 73.54 kW 100 kW = 134.10 HP so... 77 kW = 0.77 * 134.10 = 103.257 HP
Base 350 - 300 hp (224 kW) L46 - 350 hp (261 kW) LT1 - 370 hp (276 kW) LS5 - 390 hp (291 kW) LS6 - 450 hp (336 kW)
51 kW is equal to 68.34 hp
1 Hp = o.735 KW
1 KW = 1.3410220895950277 HP
The conversion factor for converting from kW to horsepower is 1.34. So, kW x 1.34 = hp
1.1L 50 PS (49 hp/37 kW) I41.3L 60 PS (59 hp/44 kW) I41.5L 70 PS (69 hp/51 kW) I41.6L 75 PS (74 hp/55 kW) I41.6L 110 PS (108 hp/81 kW) I4 (GTI)1.8L 112 PS (110 hp/82 kW) I4 (GTI/GLI)Diesel engines:1.5L 50 PS (49 hp/37 kW) I41.6L 54 PS (53 hp/40 kW) I41.6L 70 PS (69 hp/51 kW) I4 TDUSA/CDN/Japan:1.6L 60 hp (45 kW) I4 (Pickup)1.5L 70 hp (52 kW) I4 (MY 1975)1.6L 71 hp (53 kW) I4 (MY 1976)1.6L 78 hp (58 kW) I4 (MY 1977)1.5L 71 hp (53 kW) I4 (MY 1978/79)1.5L 62 hp (46 kW) I4 (MY 1980)1.6L 76 hp (57 kW) I4 (MY 1980)1.7L 74 hp (55 kW) I4 (MY 1981/82)1.7L 65 hp (48 kW) I4 (MY 1983/84)1.8L 90 hp (67 kW) I4 (GTI MY 1983/84)Diesel engines:1.5L 48 hp (36 kW) I4 (MY 1978-80)1.6L 52 hp (39 kW) I4 (MY 1981-84)1.6L 68 hp (51 kW) I4 (MY 1983-