Photon energy can be increased by following two methods.
1). by increase in frequency of one photon as (E = hf); where f denotes the frequency of corresponding region. In this case, the electromagnetic region will change to higher frequency region or shorter wavelength region. The photon energy may increase, but not the intensity.
2). secondly increase in the number of photons (n) as E= nhf. If the number of photons of a particular frequency increase, photon energy also increases. In this case, intensity of light of definite frequency (either blue, red etc.) increase simultaneously.
Photons at the red end of the visible spectrum have the longest wavelength and lowest frequency,
and carry the least energy.
Photons at the violet end of the visible spectrum have the shortest wavelength and highest frequency,
and carry the most energy.
A photon's colour is related to it's frequency, and a higher frequency means greater energy. As the question is relating to photon colour, then I assume that these are photon wavelengths that make up the visible light part of the spectrum. Therefore, photons of red light have the lowest frequency and therefore the least energy. Whereas, photons of violet have the highest frequency and therefore the greatest energy.
Photon is electromagnetic radiation which comes from the sun. There are different types of light which include: visible, ultraviolet, and infrared. Photon energy is measured in wavelengths (nanometers- nm). The shorter the wavelength, the higher the energy.
Visible light measures between 400 nm and 700 nm
Energy is proportional to frequency, or colour in the case of light. E=hf where h is Planck's Constant.
En electromagnetic wave is assimilable to a photon. The energy of a photon is equal to its frequency (that determines its "color") multiplied by the Planck's constant (h).
The energy is released as electromagetic energy and each transition in each atom has its own wavelength for the light emitted.
The highest energy photon the eye can sense has been called the color violet.
As electrons are excited by incoming photons, they jump out of their normal orbitals into higher energy states. They quickly soon after fall back into their normal energy state (their ground state). As they fall back into their ground state, they must give off some of their energy, which they do in the form of a photon. The "size" of the jump back to their ground state determines what color this photon will be. Because each molecule has different "spacing" between energy states, they give off different colored photons. This determines the color of an object.
The longer the wavelength of light, the smaller its frequency, and the less energy there is for every photon.
En electromagnetic wave is assimilable to a photon. The energy of a photon is equal to its frequency (that determines its "color") multiplied by the Planck's constant (h).
No. The color of the electron depends on the energy difference between the levels from/to which it is changing.
Red color
Each photon of blue light has more energy than a photon of any other color, because the blue ones have the highest frequency.
Wavelength, Frequency, or Photon Energy
The energy is released as electromagetic energy and each transition in each atom has its own wavelength for the light emitted.
The highest energy photon the eye can sense has been called the color violet.
A photon's energy is directly proportional to its frequency (inversely proportional to its wavelength).In any given interval of the spectrum, the highest frequency (shortest wavelength) carries the most energy.For visible light, that corresponds to the violet end of the 'rainbow'. The last color your eyes can perceiveat that end is the color with the most energy per photon.
Frequency, color, energy in each photon.
This is a tricky question because there is more than one form of energy in light. There is the energy that each particle of light (the photon) has and there is group energy which is the sum total of all the photon energy as they travel as a group (like in a laser beam). But the good news is that the answer is FALSE for both the photon and group energies. Photon energy depends on the photon fundamental frequency. And the higher the energy the bluer the color, which can run from red to violet. Those photons in the violet color have higher energy than photons in the red color frequency. And group energy is just the sum of all the photon energies in a group, like a light beam from your flashlight (aka, torch). So for a given mix of photons, the more photons in the group the higher is the group energy level. What we call light intensity (e.g., bright or dim) depends on the group energy with high energy equating to high intensity.
The smallest drop of an electron between two energy states in an atom flips out a photon of radio with a frequency of about 1,420 MHz (wavelength = about 21 centimeters).
As electrons are excited by incoming photons, they jump out of their normal orbitals into higher energy states. They quickly soon after fall back into their normal energy state (their ground state). As they fall back into their ground state, they must give off some of their energy, which they do in the form of a photon. The "size" of the jump back to their ground state determines what color this photon will be. Because each molecule has different "spacing" between energy states, they give off different colored photons. This determines the color of an object.