in molarity we dissolved no of moles of solute in 1 dm3 volume of its solution but in molality we dissolved no of moles of solute in 1000 gram or 1 kg of solvent in molarity we don't know the exact amount of solvent quantity but in mplality we know the exact volume of solvent ( water)
depends on the molarity, but it is usually pH 5.5.
Big Hairy PENIS and VAGINA
M (molarity) X V (volume) = M (molarity) X V (volume) 1.50 M X 20.7 ml = M X 90.0 ml Molarity = .345 M
Colligative properties, such as boiling point elevation, depend on the molality of the solution and the number of "entities" (ions, in this case) per formula unit. For the solutions specified, these are identical, so the answer is no.
10 -5.5= 3.2 X 10 -6 M hydronium=================
If one part of the solution is soluble, then it is an aqueous solution.
The solvent in an aqueous solution is water.
An aqueous solution contains water.
The question, as worded, is a little ambiguous. Rather, the question you should be asking is “What is the molarity of a 125 ml aqueous solution containing 10.0g of acetone?” Acetone is roughly 58 grams per mole. Therefore, a 125 mil solution with 10 g of acetone would contain roughly 0.17 moles, and the molarity would be roughly 1.4See the Related Questions for more information about how to calculate the molarity of a solution
Aqueous refers to water, so the liquid in an aqueous solution is water.
Molarity = moles of solute/Liters of solution. get moles KI 2.822 grams KI (1 mole KI/166 grams) = 0.017 moles KI ( 67.94 ml = 0.06794 Liters ) Molarity = 0.017 moles KI/0.06794 Liters = 0.2502 M KI
Any water based solution is aqueous.
1.00 * 10^-14/ 0.34 = 2.9^-14 M or (3.2e-14 M)
For an aqueous solution the solvent is water - H2O.
An aqueous solution contain a solute dissolved in water.
pH has to do with the concentration of H+ ions in the aqueous solution of acid (also known as the hydronium ion H3O+) It is found by taking the negative ln of the concentration of the H+ ions of the solution per mililiter Molarity is the amount of acid in the aqueous solution per liter. ie, if there is 12 molar HCl diluted with water in a 3:1 ratio, that solution will now be 3 molar, as it has been diluted to 25% 12 molar HCl and 75% H2O
M = n ÷ V M-Molarity (mol/l) n- moles V- volume in liters. Volume cannot be expressed in grams....
Find moles of glucose. 32.8 grams C6H12O6 (1 mole C6H12O6/180.156 grams) = 0.18206 moles C6H12O6 Molarity = moles of solute/Liters of solution M = 0.18206 moles C6H12O6/1.0 L = 0.18 M C6H12O6
an aqueous solution is a solution made of water.
anything in water is considered an aqueous solution
aqueous means liquid or water.
In an aqueous solution the solvent is water.
If the density is 1.0 g/ml, one liter of the solution will weigh 1000 grams. 3.0 % of this mass or 30 grams of it is constituted of H2O2. The molar mass of H2O2 is 2 (1.008 + 15.999) = 34.014. The molarity of this solution is therefore 30/34.014 = 0.88, to the justified number of significant digits.