image distance is the distance from the point of incidence on the mirror, the where the image is reflected to.
object distance is the distance from the actual object being reflected to the point of incidence on the mirror where it's reflected as an image.
Focal length is effective focal length of lense system, focal distance is distance (from some point in system) to focused picture. Strictly speaking, this varies as object moves nearer from infinity to system. In case of single (thin) lense, focal length is the same as focal distance from the lense, when object is in infinity.
In case of teleobjective, mirror telescope etc., focal length can be much larger than the length of the optical system. Then it is convenient to define e.g. BFL = Back focal length, which is the distance from last lense to focus point. Correspondingly, wide-angle camera lenses have much larger focal distance (and BFL) than focal length in order to give space for lifting mirror in SLR cameras.
The relation between the object distance (p), the image distance (q), and the focal length (f) of a thin lens is
(1/p) + (1/q) = 1/f
Yes it does.
In case of both mirrors and lenses, the image distance is dependent on the object distance.
Through an inverse-linear function, h=(1/d)*a, where h is viewed size/height, d is the distance of the object, and a is actual size.
1.Image distance= object distance 2.Size of the image = size of the object 3.image is laterally inverted 4.Image is always virtual & erect
Characteristics of an image formed by the plane mirror are :- * Virtual and erect (up right ) . * The image is of same size as that of the object . *The image is far behind the mirror as the object is in front of it . *The image is laterally inverted .
When the object is placed between the focal point and the mirror in a concave mirror, an enlarged virtual image equal in size to the object is formed. In this case, the image distance is greater than the object distance, and the image is virtual, upright, and magnified.
The distance from a converging lens to the object is called the object distance. It is denoted by the symbol "u" and is measured along the principal axis of the lens. The object distance affects the size and location of the image formed by the lens.
The change in size of an image compared with the size of an object is termed magnification. This can be calculated as the ratio of the size of the image to the size of the object. Magnification can be expressed as magnification = image size / object size.
1.Image distance= object distance 2.Size of the image = size of the object 3.image is laterally inverted 4.Image is always virtual & erect
Characteristics of an image formed by the plane mirror are :- * Virtual and erect (up right ) . * The image is of same size as that of the object . *The image is far behind the mirror as the object is in front of it . *The image is laterally inverted .
If the object distance is decreased in a pin hole camera, the image size will increase. If the object is too close, the full image will not be formed and the screen will appear dark.
1. Image is upright 2. Image is virtual 3. Image is of same size as object 4. Image is laterally inverted 5. Distance from object to mirror is equal to the distance from the mirror to the image
The image formed in a plane mirror is virtual, upright, the same size as the object, and laterally inverted (left becomes right and vice versa).
There is no constant ratio for image size to object size It depends on, 1. Image size 2. Sensor specifications (ex: Focal length of the camera) 3. Camera to Object distance 4. Acquisition angle (Theta) 5. Light focusing 6. Need some Known object values for determine unknown object size etc...
Image formation by a plane mirror involves reflection of light waves, where the angle of incidence is equal to the angle of reflection. The image formed is virtual, upright, and laterally inverted with respect to the object. The image appears to be the same distance behind the mirror as the object is in front of it.
Your magnification factor is SID divided by OID. [MF = SID/OID] So for example: If your SID was 40 and your SOD was 32 Your magnification factor = 40/32 = 1.25 -- This means the image will appear 25% larger than the actual object. (It's the size of 1 plus 25 percent more of the original.) Example 2 if you're trying to figure out original object size: Your object size equals your image size divided by the magnification factor (MF). [object size = image size/ MF] If you have an object on an image that measure 70 inches when your SID was 100 and your OID was 65, how big was the original object? MF=100/65= 1.54 (rounded) Object size = 65/1.54 = 42.21 The object imaged was 42.21 inches before magnification.
The size of the plan mirror should be half the size of the object to get a full size image of the object
Using the expression v/u = Image size / object size we can find the value of v. v = 15 * 3.5/13 = 4 (nearly) So approximately at a distance of 4 mm in front of the lens the image is located on the same side of the object.
Usually as we say the details of the image we point out their, size, position, type and nature. In case of plane mirror, size = same size of the object position = at the same distance as the object is in front of the mirror type - erect one nature - virtual image. This means could be seen but not be caught on a screen.
The retina