2 divided by 1 is 2 with remainder 0.
29
59
3.5
It is an integer which, when divided by 2, leaves a remainder of 1.
solve it with a calculater
65.5
33.5
86.5
449.5
2.5
17
0.0328
7 divided by 5 is 1 with remainder 2
The LCM of 2, 3, 4 and 5 is 60. Since you need a remainder of 1 just add 1. So the answer is 61. Or any number that is 1 more than a multiple of 60.
179 works until divided by 7 the remainder is 6. 2519 works till 10....
The remainder is 0.If A has a remainder of 1 when divided by 3, then A = 3m + 1 for some integer mIf B has a remainder of 2 when divided by 3, then B = 3n + 1 for some integer n→ A + B = (3m + 1) + (3n + 2)= 3m + 3n + 1 + 2= 3m + 3n + 3= 3(m + n + 1)= 3k where k = m + n + 1 and is an integer→ A + B = 3k + 0→ remainder when A + B divided by 3 is 0-------------------------------------------------------------------------From this, you may be able to see that:if A when divided by C has remainder Ra; andif B when divided by C has remainder Rb; then(A + B) divided by C will have remainder equal to the remainder of (Ra + Rb) divided by C
Put the remainder over the number you originally divided by. 15 divided by 7 = 2, remainder 1 = 2 and 1/7