To test for halide ions (Br, Cl, Fl, I) use a silver nitrate solution and then an ammonia solution. Silver nitrate solution will form a precipitate with Cl, Br, and I. Cl precipitate will be white, Br cream, and I yellow. Confirm with the ammonia solution that the AgCl dissolves into a colorless solution. AgBr will do the same but in concentrated ammonia solution. AgI is insoluble in ammonia.
Bromine is present as Br2 in the liquid and gas phases. This si a simple symmetric molecule Br-Br and has a dumbbell shape.
In the solid phase under normal pressures it is still present as Br2 molecules. It is reported that at extremely high pressures it becomes metallic which indicates that the molecular structure has changed to a Br lattice with delocalised electrons.
CBr4 will be tetrahedral because the C makes four bonds (each to Br) there are no additional unshared pairs around the C which means the only repulsion we have to worry about is the Br atoms repelling each other. Each Br is most separated if they can form bond angles of 109.5 and have a tetrahedral structure.
(tetrahedral is essential a pyramidal shape with one extra grouping on top)
The name of this compound is bromoform. See the link below for a diagram of the molecule.
The molecule of bromomethane has a tetrahedral shape.
The shape of HBr is linear.
A two-atom molecule is always linear.
Linear
H-Br
It's bent with 3 regions.
HBr
Ka = [H+].[Br-] / [HBr] However the value of this expression is very high, because HBr is a STRONG acid, meaning that much more than 99.9% of the HBr molecules in water are protolized (ionized), making [H+] and [Br-] equal to the original (added) HBr amount, and the [HBr]-value nearly zero.
HBr has a dipole
No. HBr is a strong acid.
HBr has an ionic bond.
HBr
HBr has a dipole
yes HBr is an electrolyte
Ka = [H+].[Br-] / [HBr] However the value of this expression is very high, because HBr is a STRONG acid, meaning that much more than 99.9% of the HBr molecules in water are protolized (ionized), making [H+] and [Br-] equal to the original (added) HBr amount, and the [HBr]-value nearly zero.
No. HBr is a strong acid.
C18H25NO•HBr
HBr has an ionic bond.
3.21 moles HBr (6.022 X 10^23/1mole HBr) = 1.93 X 10^24 molecules of HBr
HBr is inorganic as it does not contain carbon.
HBr can refer to hydrogen bromide, the covalent molecule and hydrobromic acid which is HBr dissolved i water.
For this you need the atomic (molecular) mass of HBr. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. HBr= 81.0 grams186 grams HBr / (81.0 grams) =2.30 moles HBr
This compound is HBr.