Math and Arithmetic

# What is the sine for greater than?

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###### 2013-02-10 14:03:15

The sign is >.

Sine is a trigonometric function.

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## Related Questions

No angle has a sine function greater than 1.

It's not. The sine of 32 degrees is approximately 0.53. The sine of 59 degrees is approximately 0.86. For a definition of sine, see: http://en.wikipedia.org/wiki/Trigonometric_function .

Sine and cosine cannot be greater than 1 because they are the Y and X values of a point on the unit circle. Tangent, on the other hand, is sine over cosine, so its domain is (-infinity,+infinity), with an asymptote occurring every odd pi/2.

You can only find the inverse of sine for number less than or greater than 1. An improper fraction is not acceptable either because the ratio is opposite over hypotenuse. The hypotenuse will always be the longest, so there you go.

No. The sine of an acute angle is less than 1. An acute angle is less than 90 degrees. The sine of 0 degrees is 0, and the sine of 90 degrees is +1. So the sines of the angles between 0 degrees and 90 degrees are less than 1.

If you look at the definition of the sine function in a triangle, you'll discover that the maximum possible value of the sine function is ' 1 ' and the minimum possible value is ' -1 '. There's no angle that can have a sine greater than ' 1 ' or less than ' -1 '. So the absolute value of the sine of anything is always ' 1 ' or less.

lol! it can be less than 1 too, upto -1! it cannot be greater than 1 because hypotenuse is always longer than the adjacent and opposite side... (from pythagoras theorem)

The sine of an angle x is defined as the ratio of the opposing side to the hypotenuse, in a right triangle having x as one of its acute angles. If it was greater than 1, it would mean the opposing side was longer than the hypotenuse. Try to draw a right triangle with one of the sides longer than the diagonal. You'll notice it's impossible. So the sine cannot be greater than 1. Fitting the triangle into a circle of radius 1, such that the angle x is located at the origin and the hypotenuse is a radius of the circle, you can define "sine of x" for any angle. Since the triangle may end up flipped in any direction, including the negative x and y axis, it turns out that the sine of any number is between -1 and +1. The cosine is simply the sine of the complementary angle (90 - x). So it must also be contained between -1 and +1.

The sine of an angle between 0 and 180 degrees is positive. The sine of an angle between 180 degrees and 360 degrees is negative. At 0, 180 and 360 degrees the sine is 0.The sine is a periodic function with period 360 degrees, so angles differing by a multitude of 360 degrees have the same sine. Hence, for instance, the sines of the angles 0, 360, 720, ... are equal, namely 0.In any right triangle the sine of one of the non-right angles will be positive, since these are greater than 0 and less than 90 degrees.

Since the hypotenuse (denominator) is always greater than the opposite or adjacent side (numerator), the ratio will always be smaller than one.

1 + cos(x) = sin(x)==> You need to find an angle whose sine is 1 greater than its cosine.The numerical values of both the sine and cosine functions range from -1 to +1.No angle has a sin or cosine less than -1 or greater than +1. That'll help us putsome constraints on the equation, and see what may be going on.The equation also says: sin(x) - cos(x) = 1This would be a great place to flash a sketch of the graphs of the sin(x) and cos(x)functions up on the screen, and see where they differ by roughly 1, with the sinebeing the greater one. It's too bad that we can't do that. The best we can do is todraw them on our scratch pad here, look at them, and tell you what we see:-- The sine is greater than the cosine only between 45&Atilde;&sbquo;&Acirc;&deg; and 225&Atilde;&sbquo;&Acirc;&deg;,so any solutions must be in that range of angles.-- At 90&Atilde;&sbquo;&Acirc;&deg;, the sine is 1 and the cosine is zero, so we have [ 1 + 0 = 1 ], and 90&Atilde;&sbquo;&Acirc;&deg; definitely works.-- At 180&Atilde;&sbquo;&Acirc;&deg;, the sine is zero and the cosine is -1, we have [ 1 + -1 = 0 ], and 180&Atilde;&sbquo;&Acirc;&deg; works.-- If there were any range between 45&Atilde;&sbquo;&Acirc;&deg; and 225&Atilde;&sbquo;&Acirc;&deg; where the graphs of the sineand cosine functions were parallel curves, then any angle in that range mightalso be a solution.But there isn't any such place. 90&Atilde;&sbquo;&Acirc;&deg; and 180&Atilde;&sbquo;&Acirc;&deg; are the only points where the valuesare different by 1 and the sine is greater, so those are the only principle solutions(answers between zero and 360&Atilde;&sbquo;&Acirc;&deg;.)

Answer #1:The exact value is (square root of 6 + square root of 2) / 4===========================Answer #2:I don't think so.The sine of almost all angles is an irrational number. 75 degrees is one of them.That means its sine can never be exactly written with numbers.The value given in Answer #1 is greater than ' 1 ', and we know that no sine canhave that value.

The sign of a number tells you if it is greater than or less than zero.The sine (abbrev. sin) of an angle relates the ratios of the lengths of the side opposite that angle and the hypotenuse in a right triangle.

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1 + cos(x) = sin(x)First of all, since you didn't include the argument of the sin or cos in the question,we sadly suspect that you have little clue as to what you're looking for, or what asolution will look like.==> You need to find an angle whose sine is 1 greater than its cosine.The numerical values of both the sine and cosine functions range from -1 to +1.No angle has a sin or cosine less than -1 or greater than +1. That'll help us putsome constraints on the equation, and see what may be going on.The equation also says: sin(x) - cos(x) = 1This would be a great place to flash a sketch of the graphs of the sin(x) and cos(x)functions up on the screen, and see where they differ by roughly 1, with the sinebeing the greater one. It's too bad that we can't do that. The best we can do is todraw them on our scratch pad here, look at them, and tell you what we see:-- The sine is greater than the cosine only between 45&Acirc;&deg; and 225&Acirc;&deg;,so any solutions must be in that range of angles.-- At 90&Acirc;&deg;, the sine is 1 and the cosine is zero, so we have [ 1 + 0 = 1 ], and 90&Acirc;&deg; definitely works.-- At 180&Acirc;&deg;, the sine is zero and the cosine is -1, we have [ 1 + -1 = 0 ], and 180&Acirc;&deg; works.-- If there were any range between 45&Acirc;&deg; and 225&Acirc;&deg; where the graphs of the sineand cosine functions were parallel curves, then any angle in that range mightalso be a solution.But there isn't any such place. 90&Acirc;&deg; and 180&Acirc;&deg; are the only points where the valuesare different by 1 and the sine is greater, so those are the only principle solutions(answers between zero and 360&Acirc;&deg;.)

The basic rule is that the sum of any two sides must be greater than the third. Then there are the sine and cosine rules which involve the lengths of the sides but also the angles.

Double the numerator. If the answer is greater than the denominator then the fraction is greater than half.Double the numerator. If the answer is greater than the denominator then the fraction is greater than half.Double the numerator. If the answer is greater than the denominator then the fraction is greater than half.Double the numerator. If the answer is greater than the denominator then the fraction is greater than half.

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