15
45.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 45 is an odd number.
45 is the smallest number that rounds to 50
45/5 = 9 45/9 = 5 Therefore, the smallest number divisible by both numbers is 45.
3.00
45.
3?
45. The LCM of 45 and 5.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 45 is an odd number.
450 is the smallest number that both 45 and 50 can divide into evenly with no remainder.
45 is the smallest number that both 9 and 15 divide into evenly with no remainder.
45 can be divided evenly by 1, 3, 5, 9, 15, and 45.
3
Yes, two can go into 45 evenly. 45 divided by 2 is equal to 22 with a remainder of 1.
45, 54, and 63 all meet those conditions.
No, not evenly. 150 divided by 45 equals 3 with a remainder of 15.
The required number is 90. The values produced by dividing 90 by 2, 3, 5, 7, and 11, the five smallest prime numbers, do not satisfy all the requirements: 90/2 = 45, which is not evenly divisible by 2; 90/3 = 30, which is not evenly divisible by 9; 90/5 = 18, which is not evenly divisible by 5; and the quotient of 90 and either 7 or 11 is not an integer itself.