If they are to be multiplied then the solution is 8
0
4+0=4 3+1=4 2+2=4 1+3=4 0+4=4 -1+5=4 -2+6=4 ...
Yes, because if you sub in for x and y, you get 4-0=4 and this is true
If you mean to say (x^2)-2x+4=0 then there is no solution for x because the equation never makes it to 0 If you mean to say 2x-2x+4=0 then there is no solution for x because it is a horizontal line at Y=4
One possible solution is x2 + (y - 4)2 = 0.
(2*4)-(1*8) = 0
Yes, because if you sub in for x and y, you get 4-0=4 and this is true
Yes, because if you sub in for x and y, you get 4-0=4 and this is true
One possible solution is x2 + (y - 4)2 = 0.
2*8 - 4*4 = 0, otherwise insert "does not" before equals.
a = 3a + 4 0 = 2a + 4 2a = -4 a = -2
Yes. x2-4x+4=0 (x-2)(x-2)=0 x=2
2*2 - 12x +16 =0 4 - 12x +16 =0 -12x + 16 +4 =0 -12x + 20 =0 -12x = -20 x = 1.666666667
4x^2 - 11x + 6 = 0 (4x - 3)(x - 2) x = 3/4, 2
I'll show work. X2-8x-4=0. X2-8x=4. X-8x=2. -7x=2. X=-(2/7).
How about x+4 = 0 ?
A number that makes an equation true is a solution. If there is more than one answer to an equation (such as an equation like): (x-2)(x+4)=0 then it is called a solution set (and in this case would be x={-4, 2}).