81 is the square root of 405.
(81 x 5 = 405.)
± 6.363961
sin(405) = square root of 2 divided by 2 which is about 0.7071067812
GM of two numbers is the square root of their product, in this case sqrt 2025 ie 45.
The perimeter of a rectangle cannot be calculated by just knowing the area unless the rectangle is a square. In which case the perimeter will be 4 x square root of the area.
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square root 2 times square root 3 times square root 8
405 is exactly 9 times the square root of five . The square root of 5 is irrational and can only be approximated with decimals.
±20.12461179749811
9 times the square root of 5
4.486
sin(405) = square root of 2 divided by 2 which is about 0.7071067812
5sqrt(405) = 5sqrt(815) = 5sqrt(81)sqrt(5) = 59sqrt(5) = 45sqrt(5)
GM of two numbers is the square root of their product, in this case sqrt 2025 ie 45.
The perimeter of a rectangle cannot be calculated by just knowing the area unless the rectangle is a square. In which case the perimeter will be 4 x square root of the area.
Best option is to use a calculator. Failing that, use the Newton-Raphson method which entails making a guess at the answer and then improving on it. Repeating the procedure should lead to a better estimate at each stage. To start with, if you want to find the square root of 405, define f(x) = x2 - 405. Then finding the square root of 405 is equivalent to solving f(x) = 0. Let f'(x) = 2x. This is the derivative of f(x) but you do not need to know that to use the N-R method. Start with x0 as the first guess. Then let xn+1 = xn - f(xn)/f'(xn) for n = 0, 1, 2, … After a few iterations, xn will be very close to the required square root. If you start with 20, whose square is 400, the second iteration gives a result that is accurate to 8 decimal places.
The square root of the square root of 2
The 8th root
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