in your radicand you have... (-5)2 - -4 x 3 x 3
this is equal to 61
remember the order of operations.
PEMDAS
P=parenthesis
E=exponents
M=multiplication
D=division
A=addition
S=subtraction
In your problem you first have to do the exponents. then you multiply the -4, 3, and 3 and the you add.
therefore your answer is sqrt(61) which is 7.81
Let square = [x] -4+3*(-2)*[-4]+[3x-2x]=-4-6-2+[x]=-12+[x]The answer is negative 12 plus squared x.
By factoring I get x-3 divided by x+3
Because multiplying negative numbers together gives a positive answer. So the square root of nine is both three and minus three.
9
0.5625.
Let square = [x] -4+3*(-2)*[-4]+[3x-2x]=-4-6-2+[x]=-12+[x]The answer is negative 12 plus squared x.
The minus (unary) operator is of lower precedence than the exponent. To force the square of a negative on some calculators you may need to surround the number in parentheses. E.g.
No. Negative three squared is POSITIVE nine. The square of ANY number is positive, because if you multiply a negative number by a negative number, the result is positive.
13
Using the quadratic formula-- ((negative b plus or minus the square root of b squared minus 4ac) divided by (2a)) you'll want to google that so you can see it in numerical form. a, b, and c are the coefficiants of your three terms ( 2 is a, -5 is b, and 2 is c) The answer is (x-2)(2x-1).
By factoring I get x-3 divided by x+3
It is: 9-4 = 5
Three times negative 2 minus three is equal to -9
-3 minus -11 is 8.
993
(-5)-(-3)-(-1)-1-3-5 (-2)-(-1)-1-3-5(-1)-1-3-5 (-2)-3-5 (-5)-5 (-10)
Negative three.