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Square root of a square is equal to?
that makes no sense if you mean square root to the power 2 its equal: the number in the root (let it =x) in absolute value then its equal=: x or -x im not sure
If X is equal to the square root of 81 what is X?
if x is equal to the square root of 81 then x is ±9 (plus or minus 9)
The square root of X-5 is a real number if and only if?
X is greater than 5. If X were equal to 5, X-5 would be 0 which has no real square root. If X were 4, X-5 would be -1 which has no real square root, and so on.
What is equal to the square root of 49 times the square root of 9?
Square root of 49 = 7... Square root of 9 = 3... 3 x 7 = 21
X2-6x plus 1 equals 0?
x2 - 6x + 1 = 0 x = [-(-6) +&- square root of [(-6)2 - 4(1)(1)]]/2(1) x = (6 +&- square root of 32)/2 x = [6 +&- 4(square root of 2)]/2 x = 3 +&- 2(square root of 2) x = 3 + 2(square root of 2) or x = 3 - 2(square root of 2) Check:
The square root of -x if x0?
If x is 0, the square root is 0 also.
What is the square root of 5 square root of 5 and so on?
Call this number "x". In this case:x = root(5 root(5 root(5 root(5... Since the expression inside the first root is equal to the entire expression, you get: x = root(5 x) Squaring both sides, to get rid of the rood, you get: x squared = 5x x squared - 5x = 0 x(x - 5) = 0 So, x is either equal to 0, or to 5. Indeed, if you start with any number and repeatedly multiply by 5 and then take the square root, you get closer and closer to 5... unless you start with zero, in which case you get exactly zero.
Square root of a square is equal to?
that makes no sense if you mean square root to the power 2 its equal: the number in the root (let it =x) in absolute value then its equal=: x or -x im not sure
If X is equal to the square root of 81 what is X?
if x is equal to the square root of 81 then x is ±9 (plus or minus 9)
The square root of X-5 is a real number if and only if?
X is greater than 5. If X were equal to 5, X-5 would be 0 which has no real square root. If X were 4, X-5 would be -1 which has no real square root, and so on.
If x is any real number then why is the square root of x2 not equal to x?
say x=-2, the x^2=4, but the square root of 4 is 2 because we always take the positive value, known as the principal root. Using this square root of x^2=|x|. So if x is greater than or equal 0, than square root of x^2 is x, but if x is less than zero we must take its abolute value.
The square root of a number x is always less than x?
No. The square roots of numbers between 0 and 1 (not including 0) are greater than or equal to (in the case of 1) the number. The square root of 0.49 is 0.7 for example.
What is the square root of -3 minus the square root of -3?
0
What is an expression with an exponent that has a value between 0 and 1?
For example, x0.5 (which is equal to the square root of x).
What the square root of zero?
0 0 x 0 = 0
What is the domain and range of y equals the square root of x plus 6?
Domian is x>-6 Range is y> or equal to 0
How do you factor x squared plus x minus one half?
(x^2+x-1/2)= x(x+1)-1/2 [x + (1 - square root of 3)/2][x + (1 + square root of 3)/2] = 0 Check it: x^2 + x/2 + (square root of 3)x)/2 + x/2 + 1/4 + (square root of 3)/4 - (square root of 3)x/2 - (square root of 3)/4 - 3/4 = 0 x^2 + x/2 + x/2 + [(square root of 3)x]/2 - [(square root of 3)x]/2 + (square root of 3)/4 - (square root of 3)/4 + 1/4 - 3/4 = 0 x^2 + x - 2/4 = 0 x^2 + x - 1/2 = 0 How to find this roots: Using the completing the square method: x^2 + x - 1/2 = 0 x^2 + x = 1/2 x^2 + x + 1/4 = 1/2 + 1/4 (x + 1/2)^2 = 3/4 x + 1/2 = (plus & minus)(square root of 3/4) x = -1/2 + (square root of 3)/2 x = - 1/2 - (square root of 3)/2
