The square root of -16 is 4 i
The square root of 16 is 4.
4
256 has two square roots: 16 and -16.
There are no real square roots of -256. But using complex numbers the square roots of -256 are 16i and -16i.
The square root of -16 is: 4 i
x=16
It is: 4 or -4
As for example the square root of 16 is 4 because 4*4 = 16
+/- 16
16 is an even number from 10 to 20, and its square roots are -4 and +4.
A positive number has two square roots, its principal (positive) root and its negative root. This is because a negative number multiplied by a negative number equals a positive number. In this instance, the square roots of 256 are 16 and -16.
16*sqrt(3) * 4*sqrt(2) = 16*4*sqrt(3)*sqrt(2) = 64*sqrt(6)
√(16/81) = (√16)/(√81) = 4/9 → The two roots are 4/9 and -4/9
It's not. Take 49 and 16 for example. The square root of the sum is the square root of 65. The sum of the square roots is 11.